Why it is not displaying Error!????
try {
$i = 9 / 0;
} catch (Exception $e) {
echo 'Error !';
}
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Shahid Karimi
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Because a warning !== an exception – Mark Baker Sep 03 '14 at 07:33
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1Because `$i = 9 / 0;` in PHP *does **not** throw an exception*. Instead it warns you: `Warning: Division by zero in FILE on line X`. – BlitZ Sep 03 '14 at 07:33
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in C# this used to throw exception. – Shahid Karimi Sep 03 '14 at 07:42