"URI is not hierarchical" when loading resource

Question

I need the URI of a file (which I put in the resources directory). If I use

MyClass.class.getClassLoader().getResource(resource)

I get

java.lang.IllegalArgumentException: URI is not hierarchical

Otherwise, if I use ClassLoader.getSystemResource(resource) it returns null.

file:/Users/user1/Library/Caches/IntelliJIdea14/plugins-sandbox/plugins/plugin/classes/disconnected.png That's the URI I get when running from the IDE. It runs like it should. But when I generate a jar and try to run it, it fails. — user2733845, Aug 23 '14 at 19:24
Try `new File(MyClass.class.getResource(resource).getPath()).toURI()` or `new File(MyClass.class.getClassLoader().getResource(resource).getPath()).toURI()` — Braj, Aug 23 '14 at 19:24
It should be relative to the top level of the jar file, not an absolute pathname. Also, I am not sure you want ir need the "file:" prefix. — James McLeod, Aug 23 '14 at 19:26
See related q http://stackoverflow.com/questions/573679/open-resource-with-relative-path-in-java — James McLeod, Aug 23 '14 at 19:28
@user3218114, it works, but it doesn't load the image when running from a jar. — user2733845, Aug 23 '14 at 19:47

score 1 · Answer 1 · answered Jun 22 '15 at 09:31

1

Are you loading the file from inside a jar? If so, the OS is unable to form a java File instance from inside a jar. To be able to load it, try open it as a Stream. "filepath" should start with a "/".

MyClass.class.getClass().getResourceAsStream( filepath );

answered Jun 22 '15 at 09:31

Peter Kennedy

481
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10

This may not work as intended in newer JVM implementations. – Krabat Jun 02 '22 at 10:28

score -1 · Answer 2 · answered Jun 30 '17 at 08:33

You should be using

getResourceAsStream(...);

when the resource is bundled as a jar/war or any other single file package for that matter.

See the thing is, a jar is a single file (kind of like a zip file) holding lots of files together. From Os's pov, its a single file and if you want to access a part of the file(your image file) you must use it as a stream.

"URI is not hierarchical" when loading resource

2 Answers2