Any canonical R way to map certain characters to replacements, tr-style?
tr ('string', 'rst', 'xyz') = 'yzxing'
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dan3
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6`chartr('rst', 'xyz', 'string')` – jdharrison Aug 19 '14 at 20:53
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I hereby accept the comment. Thank you. FWIW I did spend a few minutes searching. – dan3 Aug 19 '14 at 20:57
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I found several duplicates searching for `[r] chartr` ;) – jdharrison Aug 19 '14 at 21:02
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1It probably is a dupe, but I remember searching for a long time (more than a "few minutes" and more than once) before finding `chartr`. – IRTFM Aug 19 '14 at 21:03