Because putting NULLs inside the variables gives headache here in PHP, I resorted to explicitly putting NULL on the prepared statement
The script is a csvupload script originally came from here Import CSV into MySQL
$linemysql = implode("','",$linearray);
$linemysql = "'".$linemysql."'";
$sql="SELECT * FROM `".$tblmei."` WHERE `".$shuHint."` = ".$linearray[0];
$stmt = $setsu->query($sql);
$rwCnt=$stmt->rowCount();
if ($rwCnt==0){
$fumeiKazu=substr_count($linemysql,"'Unknown'");
echo "<br>fumeiKazu=".$fumeiKazu;
if ($fumeiKazu==1)
{
$fumeiPos=mb_strpos($linemysql,"'Unknown'");
$l1=mb_substr($linemysql,0, $fumeiPos);
echo "<br>l1=".$l1;
$sfumeiPos=$fumeiPos+9;
echo "<br>sfumeiPos=".$sfumeiPos;
$l2=mb_substr($linemysql,$sfumeiPos);
echo "<br>l2=".$l2;
echo "<br>".$l1.NULL.$l2;
$tsuika = $setsu->prepare("INSERT INTO ".$tblmei." VALUES (".$l1.NULL.$l2.")");
$tsuika->execute();
$dataHaitaKazu++;
}
}
The idea of this php script block is when it finds Unknown, post it as NULL as the row's Risk during query
I made sure the the Risk column in the table structure phpmyadmin accepts null and default is null.
This is what I came up
$tsuika = $setsu->prepare("INSERT INTO ".$tblmei." VALUES (".$l1.NULL.$l2.")");
And it yiedls this error:
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ',,'testArea','0')' at line 1' in