Why my code outputs false, what happens at if(c>b>a)?

Question

#include <stdio.h>

int main() {
int a = 10, b = 20, c = 30;
if (c > b > a)
    printf("TRUE");
else
    printf("FALSE");
return 0;
}

What happens at if(c>b>a), i know this works like if((c>b)>a),but why then false?

`c > b` is either 1 or 0 (in your case, it's 1). You want `c > b && b > a`. — T.C., Jul 13 '14 at 15:22

haccks · Accepted Answer · 2014-07-13T15:28:34.070

4

Operator > is left associative therefore c > b > a will be parenthesize as ((c > b) > a) . Since 30 is greater than 20, c > b = 1. So,

 (c > b) > a => (1 > a) => 1 > 10 => false

edited Jul 13 '14 at 15:28

answered Jul 13 '14 at 15:22

haccks

score 1 · Answer 2 · answered Jul 13 '14 at 15:23

1

c>b evaluates to 1, which is not greater than 10.

answered Jul 13 '14 at 15:23

drewbarbs

score 1 · Answer 3 · answered Jul 13 '14 at 15:25

1

c > b > a means

(c > b) > a which is false in your case..

answered Jul 13 '14 at 15:25

3 Answers3