this is example what i'm looking for.
Example:
Input: ['234','34','22','7','99']
0:0
1:0
2:3
3:2
4:2
5:0
6:0
7:1
8:0
9:2
Asked
Active
Viewed 62 times
0
Andy
- 46,308
- 56
- 161
- 219
SSR.P.S.das
- 335
- 1
- 3
- 13
-
2Have you tried yourself? – Germano Jul 02 '14 at 16:37
-
http://mattgemmell.com/what-have-you-tried/ – Andrew Gorcester Jul 02 '14 at 16:37
-
http://stackoverflow.com/questions/4664850/find-all-occurrences-of-a-substring-in-python – Anderson Green Jul 02 '14 at 16:38
1 Answers
1
joined joins all the chars into one string "2343422799"
Then we loop through the digits 0-9 and use the count method to see how many times each digit appears in the string and print the digit and the count using string formatting.
l=['234','34','22','7','99']
joined="".join(l) # joins all the chars into one string "2343422799"
for ch in range(10): # go through digits from 0-9
print "{}:{}".format(ch,joined.count(str(ch)))
0:0
1:0
2:3
3:2
4:2
5:0
6:0
7:1
8:0
9:2
Padraic Cunningham
- 168,988
- 22
- 228
- 312
-
Please add some explanation. Pure code is good, but code + explanation is much better – Barranka Jul 02 '14 at 17:08