PhP and java evaluate nested ? : differently

Question

in php

$var =  true ? '1' : false ? '2' : false ? '3' : '4';
echo $var;

output is 3

in Java

char cond =  true ? '1' : false ? '2' : false ? '3' : '4';
System.out.println( cond );

output is 1

I completely understand how Java performed the logic. but i can't get how php will output 3. need help to understand how php actually evaluated that.

I just answered a question about this a few weeks ago: http://stackoverflow.com/questions/24040555/php-calculation-why-is-11-3/24040704#24040704 — p.s.w.g, Jul 01 '14 at 03:48
That is funky! Expanding the if conditions gives the desired 1 - https://eval.in/168248. Thanks @p.s.w.g for your link aswell! — Darren, Jul 01 '14 at 03:51
@Darren Simply putting parentheses around the latter clauses should work too: `true ? '1' : ( false ? '2' : ( false ? '3' : '4' ) )` — p.s.w.g, Jul 01 '14 at 03:54

score 0 · Accepted Answer · answered Jul 01 '14 at 04:21

0

Precedence with parentheses

$var =  ((true ? '1' : false) ? '2' : false) ? '3' : '4';
echo $var;

answered Jul 01 '14 at 04:21

sectus

1 Answers1