How to get string from ASCII code in Swift?

Question

How can I get a character from a ASCII code in Apple's new Swift?

For example 65 would returns "A".

If you know the code at compile time you just can use: `println("The Character A: \u{41}")` to print arbitrary unicode scalars. See https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/StringsAndCharacters.html#//apple_ref/doc/uid/TP40014097-CH7-XID_432 and http://en.wikipedia.org/wiki/Basic_Latin_(Unicode_block) — Klaas, Sep 23 '14 at 12:12

Martin R · Accepted Answer · 2017-07-05T06:57:36.403

96

As a character:

let c = Character(UnicodeScalar(65))

Or as a string:

let s = String(UnicodeScalar(UInt8(65)))

Or another way as a string:

let s = "\u{41}"

(Note that the \u escape sequence is in hexadecimal, not decimal)

edited Jul 05 '17 at 06:57

answered Jun 22 '14 at 19:02

Martin R

Exactly what I needed. Thanks! – YourMJK Jun 22 '14 at 19:06
2

@M.J.K: See http://stackoverflow.com/questions/24102044/how-can-i-get-the-unicode-code-point-of-a-character. – Martin R Jun 22 '14 at 20:03
@nikoss: Updated so that it works with Swift 2 and 3. Thanks for letting me know! – Martin R Jul 05 '17 at 06:57

1 Answers1