How to find a regex for url value

Question

product-resource/monitor-arms/cutsheets/edge

I am trying to get "cutsheets" from the string above. I was trying to select the last "/" and get everything up to the previous "/".

Do you have any idea how to do this?

Thanks for the help-

See http://stackoverflow.com/questions/161738/what-is-the-best-regular-expression-to-check-if-a-string-is-a-valid-url — sashoalm, Jun 19 '14 at 07:48
Is it specifically 'cutsheets' you're trying to match, or do you have more URLs with different words that have to be removed/replaced? — Frank Conijn - Support Ukraine, Jun 19 '14 at 08:13
I have urls with different words. I was trying to select everything before the last "/" until another "/". — Reyjay, Jun 19 '14 at 15:06

score 0 · Answer 1 · answered Jun 19 '14 at 07:51

0

Your reasoning seems good. This should match what you need: \/([^\/]+?)\/[^\/]+?$.

Example here.

answered Jun 19 '14 at 07:51

npinti

score 0 · Answer 2 · answered Jun 19 '14 at 07:53

0

You can simply use .*/.*/(.*)/.*

(P.S. the code pasted by npinti got my the 2nd word, i.e. 'monitor-arms'. I used Expresso to check)

answered Jun 19 '14 at 07:53

H.Wolper

score 0 · Accepted Answer · answered Jun 19 '14 at 07:55

0

You could try this regex to capture the string cutsheets,

.*\/(.*)\/

OR

.*\/(.*)\/.*$

answered Jun 19 '14 at 07:55

Avinash Raj

3 Answers3