Unix cut, remove first token

Question

I'm trying to use Unix cut to remove the first two fields per line. I have input lines of of the form

(token)(whitespace)(token)(lots of text)

The problem is that there exit n tokens per line, so I can't do something like this

cut -f3,4,5,6,7,8,9

Is there a way to tell cut to take everything except the specified fields?

score 11 · Accepted Answer · answered Mar 11 '10 at 20:34

11

cut -d' ' -f3-

-d' ' might be required.

answered Mar 11 '10 at 20:34

ring bearer

score 1 · Answer 2 · answered Mar 11 '10 at 20:29

1

cut -f3-

[Body is too short? Is that new?]

answered Mar 11 '10 at 20:29

Thomas

-d' ' is not required? I think cut -d' ' -f3- would be it. – ring bearer Mar 11 '10 at 20:33
If `-d` is not given, it defaults to tabs. Actually, if "whitespace" can be both tabs and spaces, neither is right. – Thomas Mar 12 '10 at 08:54

score 0 · Answer 3 · answered Aug 13 '21 at 01:48

I tried the answer cut -d' '-f3- but it did not exclude the field. The below command worked though. I am using Linux SLES.

cut -d' ' -f3 --complement

Happy to be corrected and learn. Thank you.

score -2 · Answer 4 · edited Sep 13 '15 at 10:35

-2

You can also use AWK for this:

   awk '{$1=$2=""}1' file

edited Sep 13 '15 at 10:35

Peter Mortensen

answered Mar 12 '10 at 00:04

ghostdog74

4 Answers4