If row contains string, remove entire row

Question

Exactly as the title says, I'm trying to remove the entire row of a table if a match occurs. I have the following:

$('tr > td:nth-child(3)').text().match(/\$/g);

So in this case, if the third column contains a '$', I would want the entire row to be removed. I'm not sure how to go about this since the above only returns an array with a length of the number of matches and each index is the matched string.

Pseudo:

if($('tr > td:nth-child(3)').text().match(/\$/g)){
    $(this).remove();
}

I've been programming all day so my brain is fried, I'm sure there's something very simple I'm overlooking. Any help is appreciated.

Possible duplicate of [Regex matching table rows in HTML](https://stackoverflow.com/questions/7289181/regex-matching-table-rows-in-html) — Brian Tompsett - 汤莱恩, Oct 29 '17 at 09:03

score 3 · Answer 1 · answered Jun 18 '14 at 02:18

3

I believe you could use :contains, in this case:

$('tr > td:nth-child(3):contains("$")').remove();

answered Jun 18 '14 at 02:18

dsgriffin

64,660
17
133
135

good call, didn't even think about contains. However this removes the column, not the row. It should be `$('tr > td:nth-child(3):contains("$")').parent('tr').remove();` – pedrum golriz Jun 18 '14 at 02:24

score 3 · Accepted Answer · answered Jun 18 '14 at 02:25

3

Just a slight nuance of what null suggested will remove the entire row:

$('tr > td:nth-child(3):contains("$")').parent().remove();

jsFiddle

answered Jun 18 '14 at 02:25

Alex W

35,267
10
97
106

score 0 · Answer 3 · answered Jun 18 '14 at 02:19

0

The match method returns an array. You want to use the test method instead.

$('tr').filter(function() {
    return /\$/.test( $(this).find('td:nth-child(3)').text() );
})
.remove();

answered Jun 18 '14 at 02:19

PeterKA

22,910
4
23
48

If row contains string, remove entire row

3 Answers3