win32api determine if file is opened

Question

Using win32api, how can I determine if a file is opened?

There is an example program WhoUses.exe, but its written in C++.

Answer 1

Here's an OS agnostic version:

try:
  file = open("thefile.txt", "r+")
except IOError:
  print "File is open!"

Edited to add that your question is a duplicate of check if a file is open in Python

Answer 2

If you already have a pointer to the file:

if f.closed:
    print('file is closed')