get the last portion of the link using java regex

Question

I have an arraylist links. All links having same format abc.([a-z]*)/\\d{4}/

List<String > links= new ArrayList<>();
        links.add("abc.com/2012/aa");
        links.add("abc.com/2014/dddd");
        links.add("abc.in/2012/aa");

I need to get the last portion of every link. ie, the part after domain name. Domain name can be anything(.com, .in, .edu etc).

/2012/aa
/2014/dddd
/2012/aa

This is the output i want. How can i get this using regex? Thanks

Answer 1

Some people, when confronted with a problem, think “I know, I'll use regular expressions.” Now they have two problems.

(see here for background)

Why use regex ? Perhaps a simpler solution is to use String.split("/") , which gives you an array of substrings of the original string, split by /. See this question for more info.

Note that String.split() does in fact take a regex to determine the boundaries upon which to split. However you don't need a regex in this case and a simple character specification is sufficient.

Answer 2

Try with below regex and use regex grouping feature that is grouped based on parenthesis ().

\.[a-zA-Z]{2,3}(/.*)

Pattern description :

dot followed by two or three letters followed by forward slash then any characters

DEMO

Sample code:

Pattern pattern = Pattern.compile("\\.[a-zA-Z]{2,3}(/.*)");
Matcher matcher = pattern.matcher("abc.com/2012/aa");

if (matcher.find()) {
    System.out.println(matcher.group(1));
}

output:

/2012/aa

Note:

You can make it more precise by using \\.[a-zA-Z]{2,3}(/\\d{4}/.*) if there are always 4 digits in the pattern.

Answer 3

• Use foreach loop to iterate over list.
• Use substring and indexOf('/').

FOR EXAMPLE

String s="abc.com/2014/dddd";
System.out.println(s.substring(s.indexOf('/')));

OUTPUT

/2014/dddd

---

Or you can go for split method.

System.out.println(s.split("/",2)[1]);//OUTPUT:2014/dddd --->you need to add /

Answer 4

String result = s.replaceAll("^[^/]*","");

s would be the string in your list.

Answer 5

Some people, when confronted with a problem, think “I know, I'll use regular expressions.” Now they have two problems.

Why not just use the URI class?

output = new URI(link).getPath()

Answer 6

Try this one and use the second capturing group

(.*?)(/.*)