php multiple array values in_array

Question

I'm not sure if it's possible to do it with in_array. What I need is to verify that all given values exist in array. For example:

$a = array(1,2,3,4,5,6,7,8,9,10)
$b = array(1,2,3);

if(in_array($b, $a)) {
   return true
} else {
  return false
}

Note that all the values from $b must exist in $a in order to return true.

Maybe walk through `$b` in foreach and than test with `in_array`? — pavel, Jun 05 '14 at 18:55

num8er · Answer 1 · 2014-06-05T19:02:33.227

0

try this:

function arrayExists($needle, $haystack) {
    return sizeof(array_intersect($needle, $haystack)) == sizeof($needle);
}

also can use this if your needle array has duplicate values:

function arrayExists($needle, $haystack) {
    return sizeof(array_intersect(array_unique($needle), array_unique($haystack))) == sizeof(array_unique($needle));
}

edited Jun 05 '14 at 19:02

answered Jun 05 '14 at 18:54

num8er

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score 0 · Answer 2 · edited May 23 '17 at 12:20

0

Duplicate of Here.

Use array_diff()

$arr1 = array(1,2,3);
$arr2 = array(1,2,3,4,5,6,7);
$arr3 = array_diff($arr1, $arr2);
if (count($arr3) == 0) {
  // all of $arr1 is in $arr2
}

edited May 23 '17 at 12:20

Community

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answered Jun 05 '14 at 18:58

Orelsanpls

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score 0 · Accepted Answer · answered Jun 05 '14 at 18:59

0

$a = array(1,2,3,4,5,6,7,8,9,10);
$b = array(1,2,3);

if(!array_diff($b, $a)) {
   echo '$b is subset of $a';
} else {
  echo '$b isn`t subset of $a';
}

answered Jun 05 '14 at 18:59

voodoo417

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php multiple array values in_array

3 Answers3