How to use XPath expression to find element in an array

Question

I have few elements of the same type in my xml file and node with number of occurence that I need to use eg

<xml>
  <iteration>3</iteration>
  <myElement>123</myElement>
  <myElement>456</myElement> 
  <myElement>789</myElement>
  <myElement>012</myElement>
</xml>

Now I need to select 3rd (text of iteration node) myElement node. How to do that using XPath? I tried

(/xml/myElement)[/xml/iteration/text()]

but it doens't work. Is it possible?

Of course expected result is 789

Suggested answer does NOT fit my question. Index of element is dynamic and I needed to convert it to number before — jasiustasiu, May 30 '14 at 12:31

score 2 · Accepted Answer · answered May 30 '14 at 11:56

2

Convert the value of the iteration into a number before applying it as an indexer, viz

/xml/myElement[number(/xml/iteration/text())]

answered May 30 '14 at 11:56

StuartLC

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Thanks! SO is great :) – jasiustasiu May 30 '14 at 11:59

score 1 · Answer 2 · edited May 23 '17 at 12:20

1

There is similar question

Could you try this one: /xml/myElement[position()=/xml/iteration/text()] ?

edited May 23 '17 at 12:20

Community

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answered May 30 '14 at 11:54

Iaroslav Karandashev

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How to use XPath expression to find element in an array

2 Answers2