Pointer in the main modified in a function without pointers

Question

Let me give an example to understand my question :

void fct1()
{
 int T[20];
 int* p=T;//the goal is to modify this pointer (p)
 fct2(&p);
}
void fct2(int** p)
{
  (*p)++;//this will increment the value of the original p in the fct1
}

What i want is to avoid pointers and do it only with references , it's possible ?

Have you *tried* using a reference? What went wrong? (Also, please don't tag questions about references with [c]. There are no references in C.) — Cody Gray, May 24 '14 at 15:10
I'm working with visual c++ , and i'd like to use references but i don't know how ? — Taoufik J, May 24 '14 at 15:17

score 1 · Accepted Answer · answered May 24 '14 at 15:17

1

Yes, it can be done using references.

void fct2(int* &p) {
    p++;
}

answered May 24 '14 at 15:17

HelloWorld123456789

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this will also increment original pointer – 4pie0 May 24 '14 at 15:18
even then this is pointer and reference not only reference – 4pie0 May 24 '14 at 15:20
1

It works thank's alot ! – Taoufik J May 24 '14 at 15:20
"do it only with references", it is not what you wanted OP – 4pie0 May 24 '14 at 15:21
i mean avoiding the second pointer , sorry for being unprecise, i'm still new here ^^" – Taoufik J May 24 '14 at 15:24

score 0 · Answer 2 · answered May 24 '14 at 15:15

0

I would recommend using the iterators provided by std::array if possible:

void fct1()
{
    std::array<int, 20> l;
    auto it = l.begin();
    fct2(it);
}

template<class I>
void fct2(I& it)
{
    ++it;
}

answered May 24 '14 at 15:15

David G

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Pointer in the main modified in a function without pointers

2 Answers2