JavaScript Hoisting

Question

I was wondering, why the alert result is different after commenting out this line function a() {} ? What is the relationship between function a() and variable a?

Snippet 1:

var a = 1;
function b() {
    a = 10;
    return;
    //function a() {}
}
b();
alert(a); // 10

Snippet 2:

var a = 1;
function b() {
    a = 10;
    return;
    function a() {}
}
b();
alert(a); // 1

score 0 · Answer 1 · answered May 13 '14 at 12:50

0

It is because a is getting redefined inside of b and removes the closure.

answered May 13 '14 at 12:50

Daniel A. White

181,601
45
354
430

1

How did closure come into picture? PS: I didnt downvote – thefourtheye May 13 '14 at 12:51
`a` is being closed around in `b` in the first example. – Daniel A. White May 13 '14 at 12:55
No, in the first example, `a` is being searched in the local scope first. It isn't found. So, enclosing scope is searched (there isn't any), finally global scope is searched and we find a match. – thefourtheye May 13 '14 at 12:56

JavaScript Hoisting

1 Answers1