Python - check syntax of function code in string

Question

I am looking for code to check if a string representing a function header of a function is syntactically correct.

Here is my string example:

'''+'def __init__(self,{arg})'.format(arg = ','.join(i for i in someListOranArgPassedIn), )+''':

If this function was defined as

def __init__(self,,...a,,//b):

and goes against syntactic rules, what can I add to raise an exception?

score -1 · Answer 1 · edited May 23 '17 at 11:50

-1

Using the function from here.

import ast
def is_valid_python(code):
    try:
        ast.parse(code)
    except SyntaxError:
        return False
    return True

test_args = lambda args: "def init(self, {arg}):\n\tpass".format(arg = ",".join(args))
print is_valid_python(test_args(["a", "b"]))
print is_valid_python(test_args(["", "...a", "", "//b"]))

edited May 23 '17 at 11:50

Community

1
1

answered May 10 '14 at 03:27

dilbert

2,818
1
25
33

Fails on bare `return`. I suggest you use `compile` instead of `ast.parse`. – Veedrac May 10 '14 at 10:05
@Veedrac, I don't follow. Why would a `return` be a parameter in a function? – dilbert May 10 '14 at 10:31
`is_valid_python("return")` gives `True`; it should give `False`. Doing a full compile with `compile` catches this. – Veedrac May 10 '14 at 22:13

Python - check syntax of function code in string

1 Answers1