Python how to sort a dictionary by value in reverse order

Question

I want to sort a dictionary by value in reverse order. For example: [Red: 2, Blue: 45, Green: 100] to print Green 100, Blue 45, Red 2

Thanks

You have neglected to include any actual question, and that's no python dictionary. Please rectify this. — jonrsharpe, May 08 '14 at 21:57
You may find this post useful: http://stackoverflow.com/questions/613183/python-sort-a-dictionary-by-value — Nicholas Flees, May 08 '14 at 22:02
You could iterate through the dictionary from top to bottom. https://docs.python.org/2/c-api/dict.html the first green box. — surfmuggle, May 08 '14 at 22:26

score 2 · Answer 1 · answered May 08 '14 at 22:06

2

>>> from collections import OrderedDict

>>> a = {"Red": 2, "Blue": 45, "Green": 100}

>>> OrderedDict(sorted(a.items(), key=lambda x: x[1], reverse=True))
OrderedDict([('Green', 100), ('Blue', 45), ('Red', 2)])

answered May 08 '14 at 22:06

user3557327

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score 2 · Accepted Answer · answered May 08 '14 at 22:25

2

Use the sorted function.

d = dict(red=2, blue=45, green=100)
sorted(d.items(), cmp=lambda a,b: cmp(a[1], b[1]), reverse=True)

answered May 08 '14 at 22:25

score 1 · Answer 3 · answered May 08 '14 at 22:07

You have used the Python tag but the dictionary is not a valid Python Dictionary. This is the right structure:

{"Red": 2, "Blue": 45, "Green": 100}

So, if you want to print it here is another way:

mydic = {"Red": 2, "Blue": 45, "Green": 100}
for w in sorted(mydic, key=mydic.get, reverse=True):
  print w, mydic[w]

Python how to sort a dictionary by value in reverse order

3 Answers3