Escaping backslashes to indicate a newline

Question

If I want to search for a newline in a text using Java, should my regex be "\n" or "\\n", or will either work?

try them both on small text passage with newline and you will find out which one works. — akhilless, May 05 '14 at 21:08
possible duplicate of [Can't escape the backslash with regex?](http://stackoverflow.com/questions/4025482/cant-escape-the-backslash-with-regex) — melli-182, May 05 '14 at 21:11
Can you try this yourself? Then post the answer so that we'll all know. — Dawood ibn Kareem, May 05 '14 at 21:56

score 1 · Accepted Answer · answered May 05 '14 at 21:14

1

You aren't matching a backslahs (\) and an n, you're matching a newline character (represented as \n). There's no need to escape the backslash:

Pattern p = Pattern.compile(".*\n.*");

answered May 05 '14 at 21:14

Mureinik

It shouldn't be `.*\n` only ? If not, what are you matching after the new line ? – Pedro Lobito May 05 '14 at 21:19

1 Answers1