How can I count how many different numbers there are in one long number?
For example: this number 1122334455 has 5 different numbers.
How can I do that in Python?
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jonrsharpe
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Skizo
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2possible duplicate of [Count unique digits one liner (efficiently)](http://stackoverflow.com/questions/10752434/count-unique-digits-one-liner-efficiently) – Ashwini Chaudhary May 02 '14 at 10:59
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You should change the term `different numbers` to `different decimal digits` (assuming that's what you actually want to count). – barak manos May 02 '14 at 11:05
1 Answers
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You can do that as:
print len(set(str(s)))
The
str()casts the int as a string
Theset()takes the unique elements of the string and creates a set of it
Thelen()returns the length of the set
Examples
>>> print len(set(str(s)))
5
s = 1324082304
>>> print len(set(str(s)))
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sshashank124
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@pss, Thank you. What goods an answer to the OP if the OP is not clear what it does, right? :) – sshashank124 May 02 '14 at 10:58
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@Downvoter, Anything wrong with my answer? Please let me know so that I can improve it. Thank you – sshashank124 May 02 '14 at 11:00
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Downvoter is probably the one that doesn't understand your answer or python :P – ρss May 02 '14 at 11:01
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I often find myself puzzled as to why some members of this website choose to down-vote certain answers for no good reason. Here is +1 from me... – barak manos May 02 '14 at 11:02
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@barakmanos, I suppose its fine. They probably had a reason (or a grudge against me :)) – sshashank124 May 02 '14 at 11:03
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My program gets numbers like this: 04166666666666667. When this number become string it changes to a different number. – Skizo May 02 '14 at 11:06
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@Skizo, Why are you getting numbers starting with 0. The reason your string changes is because python considers it an octal (base-8) number – sshashank124 May 02 '14 at 11:07
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