What's the meaning of #define without replacement in C/C++?

Question

I encountered some codes as the following:

#define MY_IDENTIFIER
void someCode() 
{
    ...
    MY_IDENTIFIER
    ...
}

What's the upper code doing ?

@Cheersandhth.-Alf I clicked on your name because I though it was a link to something. — Maroun, Apr 30 '14 at 08:20

score 1 · Accepted Answer · answered Apr 30 '14 at 08:20

1

Absolutely nothing. The pre-processor is simply replacing MY_IDENTIFIER with nothing wherever it encounters it.

answered Apr 30 '14 at 08:20

RamblingMad

1

Actually, the preprocessor is. But the result is of course the same. – unwind Apr 30 '14 at 08:21

1 Answers1