PHP Regular expression - forget everything after?

Question

I have this url: http:www.blabla.com/x/x/x/x?username=testuser I need a string to read this url, but forget everything and including the ? mark. So it becomes this: http:www.blabla.com/x/x/x/x

The reason for this is because I am making this variable:

$host = $_SERVER['SERVER_NAME']  . $_SERVER['REQUEST_URI'];

And this code:

if($host == "http:www.blabla.com/x/x/x/x") {
    echo "lul";
}

But right now, the URL changes depending on what user is on, and it has to execute the echo no matter what user is on.

So I read some reges and preg_match etc. and I just wanted to hear your opinions or advice. How would I accomblish this the best? thanks!

You don't need a regex for this. Just use `strtok()`: `$result = strtok($url, '?');`. — Amal Murali, Mar 29 '14 at 16:03

score 0 · Answer 1 · answered Mar 29 '14 at 16:06

0

Or if you must omit the get / request section just explode ? and use $host[0]

answered Mar 29 '14 at 16:06

alexisdevarennes

5,165
3
23
37

score 0 · Accepted Answer · answered Mar 29 '14 at 16:06

0

This is too trivial of a task for regex.

$host = $_SERVER['SERVER_NAME'] . explode("?", $_SERVER['REQUEST_URI'], 2)[0];

(Note: this assumes you're up-to-date, or at least using PHP 5.4, for the dereference to work without a temporary variable)

answered Mar 29 '14 at 16:06

Niet the Dark Absol

311,322
76
447
566

this seems the exact type of question tht a 100l+ rep user should be answering **not** – tereško Mar 29 '14 at 16:08
@tereško My point here is to guide OP away from using regexes for something that is not a regex task. https://xkcd.com/1171/ – Niet the Dark Absol Mar 29 '14 at 16:10
... which you can do in a comment – tereško Mar 29 '14 at 16:16

PHP Regular expression - forget everything after?

2 Answers2