Is this the shortest javascript regex to find all uppercase consonants?

Question

/[B-DF-HJ-NP-TV-Z]/g

This is 20 total characters. http://regex101.com/quiz/# quiz #3 says that the shortest solution is 16 characters, but I'm not sure if that is for the JavaScript flavor of regexes.

Your regex is already 16 characters. the slashes and `g` are not part of it. — aliteralmind, Mar 28 '14 at 23:28

score 7 · Answer 1 · answered Mar 28 '14 at 23:14

7

16 char regex

(?![AEIOU])[A-Z]

answered Mar 28 '14 at 23:14

Crayon Violent

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hehehe i did the reverse one and got one char more :( – Sabuj Hassan Mar 28 '14 at 23:15
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You know what? we are always positive. Never thought in a negative way . Yeah B-) – Sabuj Hassan Mar 28 '14 at 23:16
Thanks guys, just learning regexes. Off to study the lookahead which seems pretty helpful. – Keith Grout Mar 28 '14 at 23:25
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You can make it 1 char shorter, count from `B`: `(?![EIOU])[B-Z]` – BladeMight Nov 29 '19 at 22:20

score 7 · Answer 2 · answered Mar 07 '19 at 08:15

7

this is Only ASCII, so this will the shortest regex, use Negated Character Classes, please see Negated Character Classes

[^ -AEIOU[-ÿ], 13 characters

/[^ -AEIOU[-ÿ]/g, with flag, 16 characters

answered Mar 07 '19 at 08:15

lautumn

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Doesn't work anymore `Test 5/10: Your regex is matching characters in the range 0-31, and I'm quite certain those are not consonants!` – Danny Lo Oct 18 '21 at 07:57

Jerry · Accepted Answer · 2014-03-29T00:08:53.613

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You can get it a little bit shorter by using a \P{Lu} class:

[^\P{Lu}AEIOU]

[I'm not restricting this to Javascript because regex101 is primarily PCRE flavour]

The above has 14 characters. Since the puzzle also adds in characters from the word boundaries and flags, this adds 3 more characters for //g, hence total 17 characters.

In .NET, you can do it shorter:

[B-Z-[EIOU]]

(12 chars long)

For javascript:

(?![EIOU])[B-Z]

15 chars excluding delimiters and flag.

edited Mar 29 '14 at 00:08

answered Mar 28 '14 at 23:09

Jerry

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Thanks! I'm not familiar with that notation. Anywhere I can read a little more about it and does Javascript support it? – Keith Grout Mar 28 '14 at 23:14
@KeithGrout Sorry, JS doesn't support that class. You can read more about them [here](http://perldoc.perl.org/perlunicode.html#Unicode-Character-Properties). – Jerry Mar 28 '14 at 23:17
Awesome. Your solution *is* the shortest solution per regex101 (where I mistakenly thought I was using javascript). Gotta accept the other answer since it answers exactly what I asked... No hard feelings eh? – Keith Grout Mar 28 '14 at 23:31
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@KeithGrout Huh didn't think about a shorter regex for JS until now. Edited answer =P – Jerry Mar 29 '14 at 00:10
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Thank you, I learned from this answer about `\p` and `\P`. But wait.. why is it the accepted one? `/[^\P{Lu}AEIOU]/g ` are 17 chars, not 16... – Danny Lo Oct 14 '21 at 22:26
@DannyLo That's just what the OP marked at the time... lautumn added their answer 5 years after the OP asked the question (the shortest I guess at the time of this comment) and OP is probably not around that much anymore to change it. – Jerry Oct 18 '21 at 05:44

score 3 · Answer 4 · answered Mar 28 '14 at 23:12

3

My regex is 17 characters in length! I am still one shorter!

(?=[A-Z])[^AEIOU]

Using lookahead it is first checking the next character is in between A-Z or not. Then its checking for a Non-Vowel character.

answered Mar 28 '14 at 23:12

Sabuj Hassan

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So, is this similar in execution to an if statement? For example, if(a capital letter){return !CapitalVowel} – Keith Grout Mar 28 '14 at 23:20
@KeithGrout In this particular case, yes. But its not return, its match. – Sabuj Hassan Mar 28 '14 at 23:22

Is this the shortest javascript regex to find all uppercase consonants?

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