Trying to use a wildcard with a variable in SSH comand

Asked Mar 25 '14 at 11:36

Active Mar 25 '14 at 11:37

Viewed 39 times

This will work, when i hard code the name of the file I want to find.

ANSWER=`ssh -q username@hostname'ls "/some/directory/location/availablefiles.txt" | wc -l'`

It will not work when I try to pass it a variable and a wildcard, like the below example:

For example val=available , so the command should return the file beginning with available, which would be the same as the file in the first example, availablefiles.txt

ANSWER=`ssh -q username@hostname 'ls /some/directory/location/"$val"* | wc -l'`

Any ideas? Thanks

edited Mar 25 '14 at 11:37

fedorqui

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asked Mar 25 '14 at 11:36

Blue42

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Isn't it the same as yesterday's http://stackoverflow.com/q/22612016/1983854 ? `ANSWER=$(ssh -q username@hostname "ls /some/directory/location/$val* | wc -l")` should make it. – fedorqui Mar 25 '14 at 11:37
@fedorqui yes, and that didnt work, the shell is not seeing the variable – Blue42 Mar 25 '14 at 12:30
But because you did not quote properly. It is the whole ssh command what I meant. – fedorqui Mar 25 '14 at 12:30
@fedorqui I had the quotes in in the actual script. Stack overflow removed them for some reason. the problem is with the shell not seeing the variable – Blue42 Mar 25 '14 at 13:38
Did you try what I suggested in my first comment? – fedorqui Mar 25 '14 at 13:39
@fedorqui yes. No success! :-( – Blue42 Mar 25 '14 at 14:18

Trying to use a wildcard with a variable in SSH comand

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