Run anonymous function inside another function

Question

My code:

function myFunc(callback) { /*do stuff*/
    $('div').one('mouseover', function () {
        alert('mouseover');
        callback;
    });
}
$("div").click(function () {
    alert('clicked');
    myFunc(function () {
        alert('Callback');
    });
});

However, callback does not execute, nor is there an error in the console. How can I make this work?

Fiddle: http://jsfiddle.net/8Z66u/

`callback();`. If you don't call the function, it's not executed. Function basics: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Functions#Calling_functions — Felix Kling, Mar 19 '14 at 16:19
http://jsfiddle.net/arunpjohny/8Z66u/1/ - use `console.log()` instead of `alert()` for debugging — Arun P Johny, Mar 19 '14 at 16:20
@ArunPJohny I generally do, but this is a short piece of code. — GiantDuck, Mar 19 '14 at 16:22
and [How to pass callback as a parameter into another function](http://stackoverflow.com/q/6466031/218196) — Felix Kling, Mar 19 '14 at 16:25

score 6 · Accepted Answer · answered Mar 19 '14 at 16:19

6

You are forgetting to invoke with ()

function myFunc(callback) { /*do stuff*/
    $('div').one('mouseover', function () {
        alert('mouseover');
        callback(); // invoke
    });
}

Without (), you've just got a reference to the function callback but doing no action with it, so the line basically does nothing.

answered Mar 19 '14 at 16:19

Paul S.

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I think you mean `.on('mouseover'` instead of `.one('mouseover'`. – Anonymous Mar 19 '14 at 16:22
4

@Anonymous I only want it to execute once. – GiantDuck Mar 19 '14 at 16:23
2

@Anonymous http://api.jquery.com/one/ – Paul S. Mar 19 '14 at 16:24
1

My mistake. Sorry for the confusion. – Anonymous Mar 19 '14 at 16:25

Run anonymous function inside another function

1 Answers1