C++ Shortcut with structs or arrays

Question

I do not know what this is called, I've seen something like it before. Where ever I had seen it, it said that it is not the best approach.

Items[0].x = 0; 
Items[0].y = 0; 
Items[0].width = 32; 
Items[0].height = 32; 
Items[0].name = "RandomName";

That is a better example. That is what I am doing. I was hoping there was a way to get around the Items[0]. prefix when entering the information.

You might be thinking of designated initializers from C: `struct StructOne test = {.a = 4, .b = 2, .c = 2};` (sorry if that's slightly wrong). However, there's still aggregate initialization: `StructOne test = {4, 2, 2};` and you can compose that with an array's initialization. — chris, Mar 16 '14 at 02:09
See this http://stackoverflow.com/questions/8534526/how-to-initialize-an-array-of-struct-in-c You may also look up constructors and initializer lists. — Ivarpoiss, Mar 16 '14 at 02:12
I mean like: `struct a { int b; int c; };` `a test[2];` `with test[0] // the "with" being something else` `b = 5; c = 7;` `with test[1] ` `b = 56; c = 6;` — Evan Carslake, Mar 16 '14 at 02:12

score 3 · Answer 1 · answered Mar 16 '14 at 02:50

3

CTRL+C then CTRL+V afterwards seems to work for me

answered Mar 16 '14 at 02:50

Ed Heal

score 0 · Answer 2 · answered Mar 16 '14 at 02:07

0

You want something like:

test.a = 4;
test.b = 2;
test.c = 2;

answered Mar 16 '14 at 02:07

Paul Evans

I mean like: struct a { int b; int c; }; a test[2]; with test[0] // the "with" being something else b = 5; c = 7; – Evan Carslake Mar 16 '14 at 02:11
@EvanCarslake not c++, i'm afraid – Paul Evans Mar 16 '14 at 02:29
I updated the first post, thats a copy and paste of what I am doing. Next entries would be Items[1] etc... I usually do it manually but I am hoping there is a quicker/ simpler way. – Evan Carslake Mar 16 '14 at 02:48

2 Answers2