Rounding a decimal to the nearest 0.05?

Question

How do I round a decimal to the nearest 0.05 cents in c#?

e.g $3.44 to be rounded to $3.45 or $3.48 to $3.50

I played around with math.round() though havent figured this out.

Answer 1

This has been asked many times before

Try Math.Round(val*20)/20

See round 0.05

Answer 2

Here are a couple of methods I wrote that will always round up or down to any value.

        public static Double RoundUpToNearest(Double passednumber, Double roundto)
    {

        // 105.5 up to nearest 1 = 106
        // 105.5 up to nearest 10 = 110
        // 105.5 up to nearest 7 = 112
        // 105.5 up to nearest 100 = 200
        // 105.5 up to nearest 0.2 = 105.6
        // 105.5 up to nearest 0.3 = 105.6

        //if no rounto then just pass original number back
        if (roundto == 0)
        {
            return passednumber;
        }
        else
        {
            return Math.Ceiling(passednumber / roundto) * roundto;
        }
    }
    public static Double RoundDownToNearest(Double passednumber, Double roundto)
    {

        // 105.5 down to nearest 1 = 105
        // 105.5 down to nearest 10 = 100
        // 105.5 down to nearest 7 = 105
        // 105.5 down to nearest 100 = 100
        // 105.5 down to nearest 0.2 = 105.4
        // 105.5 down to nearest 0.3 = 105.3

        //if no rounto then just pass original number back
        if (roundto == 0)
        {
            return passednumber;
        }
        else
        {
            return Math.Floor(passednumber / roundto) * roundto;
        }
    }

Answer 3

This snippet only round up to the nearest 0.05

    public static decimal Round(decimal value) {
        var ceiling = Math.Ceiling(value * 20);
        if (ceiling == 0) {
            return 0;
        }
        return ceiling / 20;
    }