Find substring from end to index of a delimiter in PYTHON

Question

I have a string say /jrfServer_domain/jrfServer_admin/HelloWorld , now all I want is HelloWorld . How can I extract it from such strings ? In this case my delimiter is / . I'm very new to python.

score 3 · Accepted Answer · edited May 23 '17 at 12:28

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Using str.rfind and slice notation:

In [725]: t='/jrfServer_domain/jrfServer_admin/HelloWorld'

In [726]: t[t.rfind('/')+1:]
Out[726]: 'HelloWorld'

edited May 23 '17 at 12:28

Community

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answered Feb 26 '14 at 09:32

zhangxaochen

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what does `t[t.rfind('/')+1:]` exactly do ? – h4ck3d Feb 26 '14 at 09:33
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@Droider `t.rfind('/')` finds the right-most index of `'/'` within `t`. If that index was stored in `k`, the expression would be `t[k+1:]` that is a string slice and means “take everything from the index `k+1` up to the end”. – poke Feb 26 '14 at 09:38
`t.rfind('/')` returns the index of the last `/` in the list, so the index of `H` from `HelloWorld` is the `+1`, and `[foo:bar]` is returning a slice – zmo Feb 26 '14 at 09:38

score 2 · Answer 2 · answered Feb 26 '14 at 09:32

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You can use str.rpartition like this

data = "/jrfServer_domain/jrfServer_admin/HelloWorld"
print(data.rpartition("/")[-1])
# HelloWorld

answered Feb 26 '14 at 09:32

thefourtheye

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`print(data.rpartition("/")[-1])` would be smarter – zmo Feb 26 '14 at 09:33
@zmo Accessing the same element in two different ways :) – thefourtheye Feb 26 '14 at 09:34
indeed, but the way I'm suggesting works whatever the `/` partitioned string is. – zmo Feb 26 '14 at 09:34
@zmo Thanks man :) But it will not matter for `rpartition` :) – thefourtheye Feb 26 '14 at 09:35
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@Droider `-1` means the least element in the result of `data.rpartition("/")`, `-2` is the last but one :) – thefourtheye Feb 26 '14 at 09:36
The thing is , I have to do this in a python script , will this work ? – h4ck3d Feb 26 '14 at 09:36
@Droider Indeed it will, please go ahead and use it :) – thefourtheye Feb 26 '14 at 09:36
will i need to import any library for this ? – h4ck3d Feb 26 '14 at 09:38
@Droider Nope, nothing is needed :) – thefourtheye Feb 26 '14 at 09:39
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No, `rpartition` exists for all strings. But seriously, just try it! – poke Feb 26 '14 at 09:39
Getting this error : [junit] [exec] AttributeError: 'string' object has no attribute 'rpartition' – h4ck3d Feb 27 '14 at 12:50
@Droider What is the version of Python? – thefourtheye Feb 27 '14 at 12:55
How can I check it ? I'm not sure as it is a part of framework – h4ck3d Feb 27 '14 at 12:58
Try `python --version` in the console – thefourtheye Feb 27 '14 at 13:00
Oh, `str.rpartition` was introduced in 2 .5 only. Sorry :) – thefourtheye Feb 27 '14 at 13:06
Yea i just figured it out , accepted the one with rfind – h4ck3d Feb 27 '14 at 13:10

score 1 · Answer 3 · answered Feb 26 '14 at 09:33

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>>> s = '/jrfServer_domain/jrfServer_admin/HelloWorld'
>>> s.split('/')[-1]
'HelloWorld'

answered Feb 26 '14 at 09:33

Tanveer Alam

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Nope, this will not be as efficient as the other methods, since it has to split the entire string based on `/` – thefourtheye Feb 26 '14 at 09:42
Yes sir I get that, I think "rfind" would be more efficient. – Tanveer Alam Feb 26 '14 at 09:46
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`s.rsplit('/', 1)[-1]` – falsetru Feb 26 '14 at 09:46

score 0 · Answer 4 · answered Feb 26 '14 at 09:35

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You can use os.path.basename:

>>> import os
>>> s = '/jrfServer_domain/jrfServer_admin/HelloWorld'
>>> os.path.basename(s)
'HelloWorld'

answered Feb 26 '14 at 09:35

flowfree

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score 0 · Answer 5 · answered Feb 26 '14 at 09:36

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>>> s=r'/jrfServer_domain/jrfServer_admin/HelloWorld'
>>> s.split('/')[-1]
'HelloWorld'

maybe you should update your delimiter in your question to "/"

answered Feb 26 '14 at 09:36

fotocoder

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Find substring from end to index of a delimiter in PYTHON

5 Answers5