fooC++ sizeof class member without instance

Question

Is this possible in C++?

I want to get the size of member, without using bar.

class foo
{
    bar member;
};

void test()
{
    new sizeof(foo::member);
}

Answer 1

You can use this:

#include <iostream>

class foo
{
   public:
      typedef int MemberType;

      MemberType member;
};

void test()
{
   std::cout << sizeof(foo::MemberType) << std::endl;
}

int main()
{
   test();
}