Get the calling Class in JavaScript

Question

Is it possible to get the class calling a function in JavaScript?

For example:

function Foo(){
this.alertCaller = alertCaller;
}
function Bar(){
this.alertCaller = alertCaller;
}

function alertCaller(){
    alert(*calling object*);
}

When calling the Foo().alertCaller() i want to output the class Foo() and when calling Bar().alertCaller() I want to outbut Bar(). Is there any way I can do this?

Answer 1

Try this :

function alertCaller(){
    alert(this.constructor);
}

Answer 2

You really should use strict mode

What is strict mode ?

I recommend you not to do what you want to do.

There is probably a better design answering to your needs.

---

If you still want to get the caller

This is what you'd use if you haven't strict mode enabled

function alertCaller(){
    alert(arguments.callee.caller);
}

Answer 3

if i understand you ..

function Foo(){
    this.alertCaller = alertCaller;
}
function Bar(){
    this.alertCaller = alertCaller;
}
Foo.prototype.alertCaller = function() { alert('Foo'); }
Bar.prototype.alertCaller = function() { alert('Bar'); }
foo = new Foo();
foo.alertCaller(); 
Bar= new Foo();
Bar.alertCaller();