how does preg_replace_callback increment and replace?

Question

I have been trying to understand how preg_replace_callback works, but I just don't get it.

Say for example, I get_contents from navigation.php. In that are a bunch of a href and divs and I want to give incremental ids to and add in some code commenting before each a href. How would I loop over all those so they would all increment and add the ids and commenting?

<?php
$string = file_get_contents("navigation.php");
$i = 1;
$replace = "<a ";
$with = '<!-- UNIT'.$i.' --><a id=a_'.$i;
$replace2 = "<div ";
$with2 = '<div id=b_'.$i;
preg_replace_callback()
$i++

?>

I figured maybe If I could get an example with my code, maybe i would be able to understand it better

so $replace and $replace2 are my strings I am searching for and $with and $with2 are the replacements respectively, and $i being the increment

so as example of data coming in

<a href="page4.php">Page 4</a>
<a href="page3.php">Page 3</a>
<div class="red">stuff</div>
<div class="blue">stuff</div>

I would want an output like..

<!-- UNIT 1 --><a id="a_1" href="page4.php">Page 4</a>
<!-- UNIT 2 --><a id="a_2" href="page3.php">Page 3</a>
<div id="b_1" class="red">stuff</div>
<div id="b_2" class="blue">stuff</div>

If you hope to have answers, please add example strings and what you want to obtain. — Casimir et Hippolyte, Feb 07 '14 at 14:45

score 0 · Accepted Answer · answered Feb 07 '14 at 15:03

You have multiple goals, the simplest way to accomplish them imo is doing it step-by-step.

1. The RegEx

You want two HTML tags, these can be caught easily via /(<a|<div)/i (explanation, g modifier is only used to demonstrate that it correctly matches).

With this you could write the following code:

$parsed = preg_replace_callback('/(<a|<div)/i', ???, $string);

2. The callback

The logic behind this can be simplified to the following switch

switch ($found) {
    case '<div':
        $result = '<div id="b_'.$id.'"';
        break;
    case '<a':
        $result = '<!-- UNIT'.$id.' --><a id="a_'.$id.'"';
        break;
    default:
        $result = "";
        break;
}

To implement this you can either write a new function or use an anonymous one. To make $id accessible, you need to learn about variable scope in PHP. An easy way out of using anything like global $id; or define() is using Closures with the use() syntax. To be able to manipulate $id (increment it), you'll need to pass it by reference (when using Closures). This brings you to the following code:

$parsed = preg_replace_callback("/(<a|<div)/", function($match) use (&$id) {
    switch ($match[1]) {
        case '<div':
            $result = '<div id="b_'.$id.'"';
            break;
        case '<a':
            $result = '<!-- UNIT'.$id.' --><a id="a_'.$id.'"';
            break;
        default:
            $result = $match[1];//do nothing
            break;
    }
    $id++;

    return $result;
}, $string);

Watch it work here.

wow, thanks for the great example! that will help a lot. One more question on this, how would I include something with a wildcard aspect? take p tags for example...if I had — Fred Turner, Feb 07 '14 at 18:32

how does preg_replace_callback increment and replace?

1 Answers1