Regular Expression - Phone Number - Android

Question

I'm trying to create a regular expression to check to see if a valid phone number has been entered. There is something wrong with my regular expression. Here is the source code I'm using:

if (!Pattern.matches("(\\d{3}-){1,2}\\d{4}", s)) {
                    et.setError("Enter a valid Phone Number");
}

What am I doing wrong?

score 24 · Accepted Answer · edited Feb 05 '14 at 20:18

24

Instead of making your own regexp, you can use Android's built in method

PhoneNumberUtils.isGlobalPhoneNumber(phoneNumber)

edited Feb 05 '14 at 20:18

Jonathon Reinhart

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answered Feb 05 '14 at 20:15

konakid

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this methods accepts 0000000000 as a valid mobile no. – Ashish Tiwari Aug 01 '18 at 07:16
Yes, that's valid. `0000000000` is my phone number, give me a call :) – Starwave Jan 25 '21 at 14:13
This method is TextUtils.isEmpty(phoneNumber) and don't work correctly. – Shahab Saalami Mar 01 '21 at 05:29

score 1 · Answer 2 · answered Feb 05 '14 at 21:47

1

This was the regular expression that fixed the issue:

(\\+[0-9]+[\\- \\.]*)?" + "(\\([0-9]+\\)[\\- \\.]*)?" + "([0-9][0-9\\- \\.]+[0-9])

answered Feb 05 '14 at 21:47

user268397

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Regular Expression - Phone Number - Android

2 Answers2