Syntax error in python 3

Question

I am new to Python and I am using python 3. I have an if statement which is recieving an error, but I do not know why. It's the line that says print new_word after the second if statement that is receiving the error. I indented it.

pyg = 'ay'

original = raw_input('Enter a word:')
word = original.lower()
first = word[0]
new_word = word[1:] + first + pyg

if len(original) > 0 and original.isalpha():
    if first == "o" or first == "i" or first == "e" or first == "u":
        print new_word
    else: print new_word
else:
    print word

Well, that one doesn't have the raw_input syntax issue as well. — munchschair, Jan 25 '14 at 20:00

score 1 · Answer 1 · answered Jan 25 '14 at 19:53

1

In Python 3.x, print is a function, so you must call it as:

print("Some string here")

Also, in Python 3.x you should use input(...) instead of raw_input(...)

answered Jan 25 '14 at 19:53

Christian Tapia

32,670
6
50
72

Ahh, I must be learning from python 2 tutorials. I am using CodeAcademy. I need to learn the differences then. – munchschair Jan 25 '14 at 19:55

Syntax error in python 3

1 Answers1