How to Extract the file name from a full path in bat?

Question

A variable %result% contains the path "D:\My Folder1\My Folder 2\My Folder 3\The Important File.txt" . I want to store The Important File in some another variable. That is, I want to extract the file name (Without extention) from a full path.

score 2 · Answer 1 · edited May 23 '17 at 10:31

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You'll find a solution here: Get the file name from a full or relative path knowing that this one is not a parameter of the batch

here: Get filename from string-path?

here: In Batch: Read only the filename from a variable with path and filename

Please search existing questions before creating duplicates.

edited May 23 '17 at 10:31

Community

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answered Jan 21 '14 at 11:58

Ben Crowhurst

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This will include the extension of the file. – Deb Jan 21 '14 at 12:00
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remove the `%~x` to truncate the extension. – npocmaka Jan 21 '14 at 12:09
Thank you both. Next time I will try to improve my search keywords. – Deb Jan 21 '14 at 18:29

score 2 · Accepted Answer · answered Jan 21 '14 at 13:40

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This should give you what you need.

@echo off
for %%a in ("%result%") do set "newvariable=%%~na"

answered Jan 21 '14 at 13:40

foxidrive

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How to Extract the file name from a full path in bat?

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