String contains any items in an array (case insensitive)

Question

How can i check if a $string contains any of the items expressed in an array?

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(contains($string,$array))
{
// do something to say it contains
}

Any ideas?

Answer 1

I don't think there is a built-in function that will handle what you want. You could easily write a contains() function however:

function contains($str, array $arr)
{
    foreach($arr as $a) {
        if (stripos($str,$a) !== false) return true;
    }
    return false;
}

Answer 2

is that what you wanted? i hope that code is compiling :)

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
  //do sth
}

Answer 3

Using the accepted answer:

$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
  //do sth
}

Just a side note that the if statement could be changed to:

if(0 < count(array_intersect(explode(' ', strtolower($string)), $array)))

since it's not really necessary to use array_map to apply strtolower to each element. instead apply it to the initial string.

Answer 4

One more workaround for contains function

function contains($string, $array, $caseSensitive = true)
{
    $stripedString = $caseSensitive ? str_replace($array, '', $string) : str_ireplace($array, '', $string);
    return strlen($stripedString) !== strlen($string);
}

PS. as for me, I'm just use it without function..

if (strlen(str_replace($array, '', $string)) !== strlen($string)) {
    // do it
}

Answer 5

Something like this would work:

$string = 'My nAmE is Tom.';
$array = array("name", "tom");
foreach ($array as $token) {
    if (stristr($string, $token) !== FALSE) {
        print "String contains: $token\n";
    }
}

Answer 6

We can check if any element of array is exists in a given string.

$string = 'My nAmE is Tom.';
$array = array("name","tom");

if(str_replace($array, '', strtolower($string)) !== strtolower($string)) {
   // If String contains an element from array      
   // Do Something
}

Answer 7

<?php

$input = preg_quote('blu', '~'); // don't forget to quote input string!
$data = array('orange', 'blue', 'green', 'red', 'pink', 'brown', 'black');

$result = preg_grep('~' . $input . '~', $data);
print_r($result);

?>

Answer 8

Will this do the job?

$words = explode(" ", $string);
$wordsInArray = array();
foreach($words as $word) {
    if(in_array($word, $array)) {
        $wordsInArray[] = $word;
    }
}

Answer 9

function contains($str, $arr)
{
  $ptn = '';
  foreach ($arr as $s) {
    if ($ptn != '') $ptn .= '|';
    $ptn .= preg_quote($s, '/');
  }
  return preg_match("/$ptn/i", $str);
}

echo contains('My nAmE is Tom', array('name', 'tom'));

Answer 10

Another way to do with array_intersect() function, Try below code :

function checkString(array $arr, $str) {

  $str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase

  $matchedString = array_intersect( explode(' ', $str), $arr);

  if ( count($matchedString) > 0 ) {
    return true;
  }
  return false;
}

Answer 11

I have done some testing because I needed to check user inputs against a list of words we didn't allow.

I have found that converting everything to lowercase (because my list is lowercase) and then using array intersect was by far the fastest.

    **First Option I Tested**
    $tempString= explode(' ',strtolower($string));
    $foundWords = array_intersect($tempString,$profanities);
    Time taken: 0.00065207481384277 

    **The second option I tested**
    $tempWords = explode(' ',$words);
    foreach ($tempWords as $word)
    {
        foreach ($profanities as $profanity)
        {
            if (stripos($word,$profanity) !== false) return true;
        }
    }
    Time Taken: 0.024131059646606

Answer 12

there is easier Method

   $string = 'My nAmE is Tom.';
   $convert=explode(" ",$string,5);
   if(in_array("My", $convert)){

      echo "Ja";
   }else{

      echo "Nein";
   }

Answer 13

Since I have to get the matching count, I used preg_match_all

preg_match_all("/" . implode(' | ', $array) . "/i", " ".str_replace([':', '-'], ' ',$string)." ", $matches);
count($matches[0]);

Answer 14

/**
 * ! Only assumes that $needles strings does not contain the character '|'
 */
function contains(string $haystack, array $needles)
{
    $regex = '/' . str_replace('\|', '|', preg_quote(implode('|', $needles))) . '/i';

    return preg_match($regex, $haystack);
}

Code demo: https://3v4l.org/lY6qo#v8.1.4

Regex demo: https://www.phpliveregex.com/p/E4s

Answer 15

Much simpler, please refer the link in_array

$os = array("Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
echo "Es Irix";
}