Python long list separated

Question

I have the following list:

x =['Adam', 'G', '24', '1983', 'Aug', 'August Birthday', 'Steve', 'F', '31', '1970', 'Sep', 'sept bday']

I would like to get the above list into another list but in a way I can work with it like this

x = [('Adam', 'G', '24', '1983', 'Aug', 'August Birthday'),('Steve', 'F', '31', '1970', 'Sep', 'sept bday')]

The Pattern is x = [(0,1,2,3,4,5),(0,1,2,3,4,5)] etc....

What is a good way to do this?

I have tried to iterate over the list using a count and after each line adding 1 to the count so I can get to 6 then start count over again, but I am not sure how to get it into the desired list.

It may also be worth looking at how that first list is generated in the first place and changing that unless you also need it in the long format. — kylieCatt, Jan 08 '14 at 20:42

Joran Beasley · Accepted Answer · 2014-01-08T20:49:06.670

3

size_of_new = 5
print zip(*[iter(x)]*size_of_new)

is my favorite way of doing this ... however

[x[i:i+size_of_new] for i in range(0,len(x),size_of_new)]

is maybe more readable

edited Jan 08 '14 at 20:49

answered Jan 08 '14 at 20:35

Joran Beasley

103,130
11
146
174

Awesome. Thank you. That works great – Trying_hard Jan 08 '14 at 20:38
I know what the asterisk means in the first example, but I am surprised by the fact that you don't put a comma between *[iter(x)] and *size_of_new. Why is this? – Totem Jan 08 '14 at 20:46
1

because its really more like `zip(*[1]*3)` => `zip(*[1,1,1])` ,whereas `zip(*[1],*3)` would result in an error – Joran Beasley Jan 08 '14 at 20:50
Your first example truncates `len(x) % size_of_new` elements at the end of list `x`. – Air Jan 08 '14 at 21:06
Yeah... But that shouldn't matter given the problem statement – Joran Beasley Jan 08 '14 at 21:50

Python long list separated

1 Answers1