Regexp excluding '\r\n'

Question

I have a string:

\r\ndsadasdsad\das\rdasdsacxz\ndasdsa\r\nadsadas\e

I want to make a regexp that will match all characters with '\' in front of them, but not "\r\n", so it would be '\.' without '\r\n'

[possibly helpful](http://stackoverflow.com/questions/406230/regular-expression-to-match-string-not-containing-a-word) — tenub, Jan 07 '14 at 16:50

revo · Accepted Answer · 2014-01-07T17:19:03.437

3

\\r(?!\\n)|(?<!\\r)\\n|\\[^rn]

edited Jan 07 '14 at 17:19

answered Jan 07 '14 at 17:09

revo

The Guy with The Hat · Answer 2 · 2014-01-07T17:21:27.583

0

This regex should match a single character that is preceded by a \, but is not part of the sequence \r\n:

(?:(?<!\\)|(?!r\\n))(?:(?<!\\r\\)|(?!n))(?<=\\).

You can find an explanation here.

edited Jan 07 '14 at 17:21

answered Jan 07 '14 at 17:09

score -1 · Answer 3 · answered Jan 07 '14 at 16:51

-1

This will match all characters which are not "n" or "r" and which have a slash in front of them.

(?<=\\)[^rn]

answered Jan 07 '14 at 16:51

mtanti

1

So it will not match \r or \n separately - I want them to be matched if they not occur together. Only when there's '\r\n' I want them not to be matched. – karlkar Jan 07 '14 at 17:00

Bryan Elliott · Answer 4 · 2014-01-08T16:42:50.827

-1

Ok, this should do what you're asking.. :

As per your question this matches "ALL characters with '\' in front of them, but not '\r\n'"

Test String:

\r\ndsadasdsad\das\rdasdsacxz\ndasdsa\r\nadsadas\e

Regex:

(?:\\r\\n\w*)|(\w+)

Matches:

MATCH 1 'das'

MATCH 2 'rdasdsacxz'

MATCH 3 'ndasdsa'

MATCH 4 'e'

edited Jan 08 '14 at 16:42

answered Jan 07 '14 at 18:36

Bryan Elliott

4 Answers4