How would I programmatically activate a window in Windows using Python? I'm sending keystrokes to it and at the moment I'm just making sure it's the last application used then sending the keystroke Alt+Tab to switch over to it from the DOS console. Is there a better way (since I've learned by experience that this way is by no means foolproof)?
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1You really should tell us what GUI toolkit you are using, because it is possible that this capability is in the toolkit. – Michael Dillon Jan 19 '10 at 01:43
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2Maybe he is trying to activate just *any* one of the open Window? – Sridhar Ratnakumar Jan 19 '10 at 03:53
5 Answers
You can use the win32gui module to do that. First you need to get a valid handle on your window. You can use the win32gui.FindWindow if you know the window class name or the exact title. If not, you can enumerate the windows with the win32gui.EnumWindows and try to find the right one.
Once you have the handle, you can call the win32gui.SetForegroundWindow with the handle. It will activate the window and will be ready for getting your keystrokes.
See an example below. I hope it helps
import win32gui
import re
class WindowMgr:
"""Encapsulates some calls to the winapi for window management"""
def __init__ (self):
"""Constructor"""
self._handle = None
def find_window(self, class_name, window_name=None):
"""find a window by its class_name"""
self._handle = win32gui.FindWindow(class_name, window_name)
def _window_enum_callback(self, hwnd, wildcard):
"""Pass to win32gui.EnumWindows() to check all the opened windows"""
if re.match(wildcard, str(win32gui.GetWindowText(hwnd))) is not None:
self._handle = hwnd
def find_window_wildcard(self, wildcard):
"""find a window whose title matches the wildcard regex"""
self._handle = None
win32gui.EnumWindows(self._window_enum_callback, wildcard)
def set_foreground(self):
"""put the window in the foreground"""
win32gui.SetForegroundWindow(self._handle)
w = WindowMgr()
w.find_window_wildcard(".*Hello.*")
w.set_foreground()
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This doesn't work when you have several instances of the same application opened at the same time, as you you wouldn't be able to distinguish between them (since it's all based on the window title). It's a real shame but I suppose this is down the Win32API rather than this particular python module? – dm76 Feb 18 '16 at 12:02
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@NullVoxPopuli hand is a handle on a window. This abbreviation is usually used in windows win32 api – luc Nov 02 '17 at 17:05
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12018-11-26. I get `ModuleNotFoundError: No module named 'win32.distutils.command'` during the installation of win32gui with pip 18.0.1, on Windows 10. – Mathieu CAROFF Nov 26 '18 at 17:43
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On certain versions of Windows `SetForegroundWindow` can cause an unexpected error. To fix you need send an alt key first, more [info](https://stackoverflow.com/questions/14295337/win32gui-setactivewindow-error-the-specified-procedure-could-not-be-found) – Yusof Bandar Jan 28 '19 at 15:14
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@luc Are you able to set foreground when the computer is locked? The script works perfectly when the screen isn't locked. However, when the script is run while the computer is locked, it will not set the foreground. – datalifenyc Sep 30 '19 at 19:08
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@myidealab Don't know how to set foreground when computer is locked. You may have to check the WIndows API to know if this is possible. – luc Oct 02 '19 at 06:09
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@luc Thanks for the feedback. The short answer is you can't. The long answer is that you would need a second pc environment (virtual or remote). I ended up taking a different approach: Python outputs 3 text files (recipients, subject, body). Outlook VBA uses the text to send the daily email. References: 1. [What happens 'behind' the windows lock screen?](https://stackoverflow.com/questions/9563549/what-happens-behind-the-windows-lock-screen/9565714#9565714) 2. [pywinauto is not working while lock screen](https://stackoverflow.com/questions/51100855/pywinauto-is-not-working-while-lock-screen) – datalifenyc Oct 03 '19 at 15:02
Pywinauto and SWAPY will probably require the least effort to set the focus of a window.
Use SWAPY to auto-generate the python code necessary to retrieve the window object, e.g.:
import pywinauto
# SWAPY will record the title and class of the window you want activated
app = pywinauto.application.Application()
t, c = u'WINDOW SWAPY RECORDS', u'CLASS SWAPY RECORDS'
handle = pywinauto.findwindows.find_windows(title=t, class_name=c)[0]
# SWAPY will also get the window
window = app.window_(handle=handle)
# this here is the only line of code you actually write (SWAPY recorded the rest)
window.SetFocus()
If by chance other windows are in front of the window of interest, not a problem. This additional code or this will make sure it is shown before running the above code:
# minimize then maximize to bring this window in front of all others
window.Minimize()
window.Maximize()
# now you can set its focus
window.SetFocus()
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4This example keeps giving me an error that the list index is out of range on line 6 (the one initializing the handle). I tried to look up info of pywinauto.findwindows.find_windows()-method, but there was none in the documentation. – EmppuTheEngineer Jun 25 '18 at 02:56
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Note: any python shell running before the installation must be restarted before using pywinautogui or it will miss a dependency at load time; Pywinauto cannot be hotplugged. – Mathieu CAROFF Nov 26 '18 at 17:49
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Thanks for the minimize maximize trick. It also solved my problem using win32gui – Amin Guermazi May 14 '20 at 23:21
import ctypes, platform
if platform.system() == 'Windows':
Active_W = ctypes.windll.user32.GetActiveWindow()
ctypes.windll.user32.SetWindowPos(Active_W,0,0,0,0,0,0x0002|0x0001)
Here we go. you just need to store the value of the active window.
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Pip install keyboard. Before you set foreground window, simulate a keyboard to esc that is keyboard.send('esc') You may want to do it three times for either of the following:
- Sidebar
- Windows key overlay
- Task manager which is always on top
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I develop in Windows environment since... a lot :) and I should be used to face absurd issues. Despite this, I'm still amazed when one happens. Thanks for this suggestion, it looks it saved my day! – Max1234-ITA Jul 14 '21 at 11:13
Using SetWindowPos or SetForegroundWindow might NOT be enough if the window was minified aka IsIconic! We can use ShowWindow with SW_RESTORE (9):
import ctypes
def activate_window(hwnd):
user32 = ctypes.windll.user32
user32.SetForegroundWindow(hwnd)
if user32.IsIconic(hwnd):
user32.ShowWindow(hwnd, 9)
Depending on how you identify the desired window there are some ways to get the hwnd aka window handle.
You could loop through all the windows to find the right handle according to the pid via user32.GetWindowThreadProcessId or by window name with user32.GetWindowTextW
To get ProcessIds you could use Windows built-in wmic. There are loads of other nifty things you can do with it. (all attributes: wmic process get /?) (get handle is broken tho) For example:
def get_pids(proc_name):
out = subprocess.check_output('wmic process where Name="%s" get ProcessId' % proc_name)
pids = out.decode().strip().split()[1:]
if not pids:
raise WindowsError('Could not find pids for process')
return [int(pid) for pid in pids]
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