How to find a specific word in an URL?

Question

I have a string called "URL" which stores the url which comes dynamically. Now I would like to show whether the url from youtube or vimeo or facebook or google.

String URL = "https://www.youtube.com/watch?v=M0jmSsQ5ptw"; // this comes dynamically in my code

if [URL contains youtube word ] [ print "URL from YOUTUBE" ]

if [URL contains facebook word ] [ print "URL from FACEBOOK" ]

if [URL contains google word ] [ print "URL from GOOGLE" ]

if [URL contains vimeo word ] [ print "URL from VIMEo" ]

please help me how to find a word in a url.

http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#contains(java.lang.CharSequence) — Asterisk, Dec 13 '13 at 06:57
have you taken a look at String.contains() /String.indexOf() ? — Satya, Dec 13 '13 at 06:57
http://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java?rq=1 — Surabhil Sergy, Dec 13 '13 at 06:58

score 1 · Accepted Answer · edited Dec 13 '13 at 07:02

1

use url.contains("whatyouwant")

ref : http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

edited Dec 13 '13 at 07:02

codelovesme

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answered Dec 13 '13 at 06:57

Deepak

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score 0 · Answer 2 · answered Dec 13 '13 at 06:58

0

Try split()

    String URL = "https://www.youtube.com/watch?v=M0jmSsQ5ptw";
    System.out.println("URL from "+URL.split("\\.")[1].toUpperCase());

Output:

URL from YOUTUBE

answered Dec 13 '13 at 06:58

Rakesh KR

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score 0 · Answer 3 · answered Dec 13 '13 at 06:58

0

you already answered your own question.

if [URL contains google word ] [ print "URL from GOOGLE" ]

if(URL.contains("google"))
print("URL from GOOGLE")

answered Dec 13 '13 at 06:58

Foolish

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:) Welcome to Stackoverflow – Foolish Dec 13 '13 at 07:07

score 0 · Answer 4 · answered Dec 13 '13 at 07:01

0

url.toLowerCase().contains("dynamic code");
system.out.println(url+" from "+ dynamic code;

answered Dec 13 '13 at 07:01

lawonga

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How to find a specific word in an URL?

4 Answers4