How to copy a char pointer into a char array?

Question

So I have a pointer to a char array:

temporaryVariable->arrayOfElements; // arrayOfElements is char*

I would like to copy into my char array declared with square brackets:

char stringArray[MAXIMUM_LINE_LENGTH + 1];

How can I do this?

score 5 · Accepted Answer · answered Nov 28 '13 at 22:34

5

Use strncpy:

strncpy(stringArray, temporaryVariable->arrayOfElements, sizeof(stringArray));
stringArray[sizeof(stringArray) - 1] = '\0';

answered Nov 28 '13 at 22:34

user4815162342

I'd also note he could check before hand to see if it would fit if truncating the string is not suitable – Keith Nicholas Nov 28 '13 at 22:35

score 1 · Answer 2 · answered Nov 29 '13 at 01:06

1

snprintf(stringArray,MAXIMUM_LINE_LENGTH + 1,"%s",temporaryVariable->arrayOfElements);

answered Nov 29 '13 at 01:06

freedoo

2 Answers2