convert string containing a hex value into a char byte in c

Question

Hey guys I am working with a software that needs to check for a char byte lets say like this:

char id = 0xa2;

As we all know that is a char byte in hex, what I need is a way to read from a txt file that same hex number, and compare it with id. As you may notice when you read from a file what you have is a char pointer containing the string let's say 0xa2 I need a way that I could compare the two values to check if it is the same ID obviously I know that one of the two values have to be converted to match the other, I just dont know how to do it and I have tried several methods

score 3 · Answer 1 · edited May 23 '17 at 12:06

3

You could use a modification of the following answers:

edited May 23 '17 at 12:06

Community

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answered Nov 28 '13 at 16:10

Igor Ševo

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score 0 · Accepted Answer · answered Nov 28 '13 at 16:10

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Simplest is to convert the char to a string. E,g,

char idStr[5];
sprintf(idStr, "0x%02x", (unsigned char)id);

The compare idStr with the string read from the file.

Case might be an issue, obviously 0xA2 and 0xa2 should compare equal.

answered Nov 28 '13 at 16:10

john

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thanks @jhon you gave a nice idea I did it that way then I compare the two strings with a little function I created and pum working fine good stuff – user2948982 Nov 29 '13 at 15:11

score 0 · Answer 3 · answered Nov 28 '13 at 16:23

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I can suggest the following solution. Instead of a file stream I am using a string stream.

    std::istringstream is( "0xa2" );

    char id = '\xa2';

    int x;

    is >> std::hex >> x;

    if ( id == static_cast<char>( x ) ) std::cout << "They are equal each other" << std::endl;

answered Nov 28 '13 at 16:23

Vlad from Moscow

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Thanks bro but I am using plain C cannot c++ – user2948982 Nov 29 '13 at 15:12

convert string containing a hex value into a char byte in c

3 Answers3