Javascript regex matching on a time

Question

I want to see if the string I have is in the form of HH:MM:SS.

Here is what I have so far:

d = '00:01:01'
d.match(/\d{2}:\d{2}:\d{2}/)
["00:01:02"]

Is there a way to just get a True/False, instead of an array?

http://stackoverflow.com/questions/8318236/regex-pattern-for-hhmmss-time-string check this — X-Pippes, Nov 19 '13 at 21:11
an array is "true-ish" ... so you can still check `if(d.match(...))` — devnull69, Nov 19 '13 at 21:13
ahem ... I just told you, didn't I? You just need to replace the `...` in my answer with the RegEx you already have — devnull69, Nov 19 '13 at 21:15
you can also use .test() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/test — peterchon, Nov 19 '13 at 21:15

score 1 · Answer 1 · answered Nov 19 '13 at 21:28

1

Use .test method of Regexp object.

/\d{2}:\d{2}:\d{2}/.test(d)
// true

answered Nov 19 '13 at 21:28

Oleg V. Volkov

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score 0 · Accepted Answer · edited May 23 '17 at 12:19

Perhaps, you can use regex.test(str) but it's also possible using match because on success, match returns an array which is a truthy value and on failure, match returns null which is a falsy value. Check this to understand truthy and falsy.

So, if you use

if(d.match(/\d{2}:\d{2}:\d{2}/)) {
    // true
}
else {
    // false
}

This will work, check this fiddle as an example and this answer as well (about !!), I've used !! in my example, so you may have doubts.

Javascript regex matching on a time

2 Answers2