I have a time as a number of milliseconds and I want to convert it to a HH:MM:SS format. It should wrap around, with milliseconds = 86400000 I want to get 00:00:00.
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23 Answers
How about creating a function like this:
function msToTime(duration) {
var milliseconds = Math.floor((duration % 1000) / 100),
seconds = Math.floor((duration / 1000) % 60),
minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds + "." + milliseconds;
}
console.log(msToTime(300000))
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I have used this way for convert milliseconds to hours:minutes:seconds format.but i did not get it correctly.it is giving only 21:11:05 for all milliseconds.how can i implement this? – cheliyan Nov 09 '13 at 10:19
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1var s = st_date+' '+start; var e = end_date+' '+end; var bits = s.split(/\D/); var bits1 = e.split(/\D/); var date = new Date(bits[0], --bits[1], bits[2], bits[3], bits[4],bits[5]); var date1 = new Date(bits1[0], --bits1[1], bits1[2], bits1[3], bits1[4],bits1[5]); – cheliyan Nov 09 '13 at 10:21
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var t1=date.getTime() var t2=date1.getTime() var t3=date1.getTime()-date.getTime(); var seconds; var minutes; var milliseconds = parseInt((t3%1000)/100) , seconds = parseInt((t3/1000)%60) , minutes = parseInt((t3/(1000*60))%60) , hours = parseInt((t3/(1000*60*60))%24); hours = (hours < 10) ? "0" + hours : hours; minutes = (minutes < 10) ? "0" + minutes : minutes; seconds = (seconds < 10) ? "0" + seconds : seconds; duration=hours + ":" + minutes + ":" + seconds; alert('dur::'+t3); alert('duration:'+duration); – cheliyan Nov 09 '13 at 10:21
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that is my code for your consideration.please check it and help me.thanks in advance.... – cheliyan Nov 09 '13 at 10:22
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2If duration input param is already in milliseconds, why do you divide by 100 to get milliseconds? Shouldn't it be just parseInt(duration % 1000)? – NoBullMan Jul 28 '20 at 17:15
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can anyone tell me why dividing milliseconds by 100 ? – akash patel Nov 21 '20 at 19:04
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@akashpatel @NoBullMan the `/ 100` is throwing out everything past 1/10th of a second precision. So `msToTime(100)` returns `00:00:00.1` and `msToTime(99)` returns `'00:00:00.0'` – Boris Verkhovskiy Mar 31 '21 at 04:09
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3should be `var milliseconds = Math.floor(duration % 1000),` – pseudozach May 25 '21 at 16:14
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This is a great answer. However, it does truncate the ms when < 1000. Rewriting `milliseconds = Math.floor((duration % 1000) / 100)` as `milliseconds = Math.floor(duration % 1000)` fixes this – 2Toad Jul 30 '21 at 18:40
To Convert time in millisecond to human readable format.
function msToTime(ms) {
let seconds = (ms / 1000).toFixed(1);
let minutes = (ms / (1000 * 60)).toFixed(1);
let hours = (ms / (1000 * 60 * 60)).toFixed(1);
let days = (ms / (1000 * 60 * 60 * 24)).toFixed(1);
if (seconds < 60) return seconds + " Sec";
else if (minutes < 60) return minutes + " Min";
else if (hours < 24) return hours + " Hrs";
else return days + " Days"
}
console.log(msToTime(1000))
console.log(msToTime(10000))
console.log(msToTime(300000))
console.log(msToTime(3600000))
console.log(msToTime(86400000))
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4I found this one the most useful, the top answer didn't seem to handle hours very well in my testing and this also gives you the options of days. – ak85 Apr 09 '16 at 04:29
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5To me this answer is not helpful. What does "3.7" hours mean??? – Sartheris Stormhammer Jul 15 '21 at 13:17
I had the same problem, this is what I ended up doing:
function parseMillisecondsIntoReadableTime(milliseconds){
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h + ':' + m + ':' + s;
}
var time = parseMillisecondsIntoReadableTime(86400000);
alert(time);
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Here is my solution
let h,m,s;
h = Math.floor(timeInMiliseconds/1000/60/60);
m = Math.floor((timeInMiliseconds/1000/60/60 - h)*60);
s = Math.floor(((timeInMiliseconds/1000/60/60 - h)*60 - m)*60);
// to get time format 00:00:00
s < 10 ? s = `0${s}`: s = `${s}`
m < 10 ? m = `0${m}`: m = `${m}`
h < 10 ? h = `0${h}`: h = `${h}`
console.log(`${s}:${m}:${h}`);
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4I'd set value to s outside the ternary operator: `s = \`${s < 10 ? '0': ''}${s}\` ` – seniorpreacher Jun 23 '20 at 21:07
This one returns time like youtube videos
function getYoutubeLikeToDisplay(millisec) {
var seconds = (millisec / 1000).toFixed(0);
var minutes = Math.floor(seconds / 60);
var hours = "";
if (minutes > 59) {
hours = Math.floor(minutes / 60);
hours = (hours >= 10) ? hours : "0" + hours;
minutes = minutes - (hours * 60);
minutes = (minutes >= 10) ? minutes : "0" + minutes;
}
seconds = Math.floor(seconds % 60);
seconds = (seconds >= 10) ? seconds : "0" + seconds;
if (hours != "") {
return hours + ":" + minutes + ":" + seconds;
}
return minutes + ":" + seconds;
}
Output:
- getYoutubeLikeToDisplay(129900) = "2:10"
- getYoutubeLikeToDisplay(1229900) = "20:30"
- getYoutubeLikeToDisplay(21229900) = "05:53:50"
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comment - does not work correctly for negative time for example `-3000` should show `-00:03` but it returns `-1:0-03`. – anu May 03 '19 at 18:01
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I made some improvements/adjustments https://stackoverflow.com/a/67462589 – Sinjai May 09 '21 at 21:56
Sorry, late to the party. The accepted answer did not cut it for me, so I wrote it myself.
Output:
2h 59s
1h 59m
1h
1h 59s
59m 59s
59s
Code (Typescript):
function timeConversion(duration: number) {
const portions: string[] = [];
const msInHour = 1000 * 60 * 60;
const hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + 'h');
duration = duration - (hours * msInHour);
}
const msInMinute = 1000 * 60;
const minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + 'm');
duration = duration - (minutes * msInMinute);
}
const seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + 's');
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 1000)));
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Thanks man, this is what I wanted. Had to adapt slightly to show '0h 0m 10s' etc but otherwise clean and simples – HazeyAce Apr 12 '20 at 20:02
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I started writing my own, then I thought, somebody must have done this already :). Thank you! – Ben S Apr 28 '20 at 13:32
The above snippets don't work for cases with more than 1 day (They are simply ignored).
For this you can use:
function convertMS(ms) {
var d, h, m, s;
s = Math.floor(ms / 1000);
m = Math.floor(s / 60);
s = s % 60;
h = Math.floor(m / 60);
m = m % 60;
d = Math.floor(h / 24);
h = h % 24;
h += d * 24;
return h + ':' + m + ':' + s;
}
Thanks to https://gist.github.com/remino/1563878
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1To have more humanized output you can return something like: return ((h + '').length === 1 ? '0'+ h : h) + ':' + ('0' + m).substr(-2) + ':' + ('0' + s).substr(-2); – Vitall Mar 13 '19 at 09:20
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@Vitall Just use `return (h < 10 ? "0" + h : h) + ":" + (m < 10 ? "0" + m : m) + ":" + (s < 10 ? "0" + s : s);`, because it's way better doing this with math than a bunch of string manipulation. – Mitch McMabers Feb 22 '20 at 13:12
I needed time only up to one day, 24h, this was my take:
const milliseconds = 5680000;
const hours = `0${new Date(milliseconds).getHours() - 1}`.slice(-2);
const minutes = `0${new Date(milliseconds).getMinutes()}`.slice(-2);
const seconds = `0${new Date(milliseconds).getSeconds()}`.slice(-2);
const time = `${hours}:${minutes}:${seconds}`
console.log(time);
you could get days this way as well if needed.
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This solution uses one function to split milliseconds into a parts object, and another function to format the parts object.
I created 2 format functions, one as you requested, and another that prints a friendly string and considering singular/plural, and includes an option to show milliseconds.
function parseDuration(duration) {
let remain = duration
let days = Math.floor(remain / (1000 * 60 * 60 * 24))
remain = remain % (1000 * 60 * 60 * 24)
let hours = Math.floor(remain / (1000 * 60 * 60))
remain = remain % (1000 * 60 * 60)
let minutes = Math.floor(remain / (1000 * 60))
remain = remain % (1000 * 60)
let seconds = Math.floor(remain / (1000))
remain = remain % (1000)
let milliseconds = remain
return {
days,
hours,
minutes,
seconds,
milliseconds
};
}
function formatTime(o, useMilli = false) {
let parts = []
if (o.days) {
let ret = o.days + ' day'
if (o.days !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.hours) {
let ret = o.hours + ' hour'
if (o.hours !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.minutes) {
let ret = o.minutes + ' minute'
if (o.minutes !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.seconds) {
let ret = o.seconds + ' second'
if (o.seconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (useMilli && o.milliseconds) {
let ret = o.milliseconds + ' millisecond'
if (o.milliseconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (parts.length === 0) {
return 'instantly'
} else {
return parts.join(' ')
}
}
function formatTimeHMS(o) {
let hours = o.hours.toString()
if (hours.length === 1) hours = '0' + hours
let minutes = o.minutes.toString()
if (minutes.length === 1) minutes = '0' + minutes
let seconds = o.seconds.toString()
if (seconds.length === 1) seconds = '0' + seconds
return hours + ":" + minutes + ":" + seconds
}
function formatDurationHMS(duration) {
let time = parseDuration(duration)
return formatTimeHMS(time)
}
function formatDuration(duration, useMilli = false) {
let time = parseDuration(duration)
return formatTime(time, useMilli)
}
console.log(formatDurationHMS(57742343234))
console.log(formatDuration(57742343234))
console.log(formatDuration(5423401000))
console.log(formatDuration(500))
console.log(formatDuration(500, true))
console.log(formatDuration(1000 * 30))
console.log(formatDuration(1000 * 60 * 30))
console.log(formatDuration(1000 * 60 * 60 * 12))
console.log(formatDuration(1000 * 60 * 60 * 1))
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Worked for me
msToTime(milliseconds) {
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h == "00" ? m + ':' + s : h + ':' + m + ':' + s;
}
Human-readable code for human-readable output and you can extend this to light years or nanoseconds or what have you very intuitively. Obviously you'd want to convert this to a function and re-use some of those intermediate modulo calls.
second = 1000
minute = second * 60
hour = minute * 60
day = hour * 24
test = 3 * day + 2 * hour + 11 * minute + 58 * second
console.log(Math.floor(test / day))
console.log(Math.floor(test % day / hour))
console.log(Math.floor(test % day % hour / minute))
console.log(Math.floor(test % day % hour % minute / second))
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Format as hh:mm:ss with optional padding
(1:59:59 or 01:59:59)
(1:59 or 01:59)
(Default: no padding)
Based loosely on Chand's answer.
function formatMilliseconds(milliseconds, padStart) {
function pad(num) {
return `${num}`.padStart(2, '0');
}
let asSeconds = milliseconds / 1000;
let hours = undefined;
let minutes = Math.floor(asSeconds / 60);
let seconds = Math.floor(asSeconds % 60);
if (minutes > 59) {
hours = Math.floor(minutes / 60);
minutes %= 60;
}
return hours
? `${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}`
: `${padStart ? pad(minutes) : minutes}:${pad(seconds)}`;
}
Tests:
let s = 1000;
let m = 60*s;
let h = 60*m;
console.log(formatMilliseconds(1*h)); // 1:00:00
console.log(formatMilliseconds(1*h, true)); // 01:00:00
console.log(formatMilliseconds(59*m + 59*s)); // 59:59
console.log(formatMilliseconds(59*m + 59*s, true)); // 59:59
console.log(formatMilliseconds(9*m + 9*s)); // 9:09
console.log(formatMilliseconds(9*m + 9*s, true)); // 09:09
console.log(formatMilliseconds(5*s)); // 0:05
console.log(formatMilliseconds(5*s, true)); // 00:05
console.log(formatMilliseconds(2400*s)); // 40:00
console.log(formatMilliseconds(2400*s, true)); // 40:00
.
.
.
If you need millisecond precision, you can get the fractional part using the following:
(asSeconds % 1).toFixed(3).substring(1)
Your returns would end up looking like this (break it up for readability as necessary):
`${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`
There are probably better ways to do that, but this naive solution gets the job done.
Test:
let asSeconds = 59.5219;
let seconds = Math.floor(asSeconds);
console.log(`${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Equivalent to above, without using `pad()`:
//console.log(`${String(seconds).padStart(2, '0')}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Output: 59.522
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This doesn't fulfill OP's requirement of 24 hours wrapping around to 00:00:00 (but then aren't you expressing a time on the clock rather than a duration?) – Sinjai May 10 '21 at 20:09
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This is probably a more sensible and idiomatic way to get just the decimal plus 3 digits: secondString = asSeconds.toFixed(3); secondString.substring(secondString.indexOf('.')); – Sinjai Nov 30 '21 at 22:48
Based on @Chand answer. This is the implementation in Typescript. A bit safer than coercing types in JS. If you remove the type annotation should be valid JS. Also using new string functions to normalise the time.
function displayTime(millisec: number) {
const normalizeTime = (time: string): string => (time.length === 1) ? time.padStart(2, '0') : time;
let seconds: string = (millisec / 1000).toFixed(0);
let minutes: string = Math.floor(parseInt(seconds) / 60).toString();
let hours: string = '';
if (parseInt(minutes) > 59) {
hours = normalizeTime(Math.floor(parseInt(minutes) / 60).toString());
minutes = normalizeTime((parseInt(minutes) - (parseInt(hours) * 60)).toString());
}
seconds = normalizeTime(Math.floor(parseInt(seconds) % 60).toString());
if (hours !== '') {
return `${hours}:${minutes}:${seconds}`;
}
return `${minutes}:${seconds}`;
}
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1JS is evolving towards TypeScript. This will probably be valid JS soon. :-) – N8allan Oct 17 '18 at 17:28
Extending on @Rick's answer, I prefer something like this:
function msToReadableTime(time){
const second = 1000;
const minute = second * 60;
const hour = minute * 60;
let hours = Math.floor(time / hour % 24);
let minutes = Math.floor(time / minute % 60);
let seconds = Math.floor(time / second % 60);
return hours + ':' + minutes + ":" + seconds;
}
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I like this, but what if minutes, for example, is < 10? Can you add padding? – ndtreviv Mar 31 '22 at 19:52
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@ndtreviv, no, it doesn't but you can add it easily, look at Shady's answer – Mustapha-Belkacim Apr 01 '22 at 07:56
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// The following is written in Typescript, should be easy to translate to JS
function humanReadableDuration(msDuration: int): string {
const h = Math.floor(msDuration / 1000 / 60 / 60);
const m = Math.floor((msDuration / 1000 / 60 / 60 - h) * 60);
const s = Math.floor(((msDuration / 1000 / 60 / 60 - h) * 60 - m) * 60);
// To get time format 00:00:00
const seconds: string = s < 10 ? `0${s}` : `${s}`;
const minutes: string = m < 10 ? `0${m}` : `${m}`;
const hours: string = h < 10 ? `0${h}` : `${h}`;
return `${hours}h ${minutes}m ${seconds}s`;
}
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my solution
var sunriseMills = 1517573074000; // sunrise in NewYork on Feb 3, 2018 - UTC time
var offsetCityMills = -5 * 3600 * 1000; // NewYork delay to UTC
var offsetDeviceMills = new Date().getTimezoneOffset() * 60 * 1000 ; // eg. I live in Romania (UTC+2) >> getTimezoneOffset() = 120
var textTime = new Date(sunriseMills + offsetCityMills + offsetDeviceMills)
.toLocaleTimeString('en-US', { hour: 'numeric', minute: 'numeric' });
textTime will become '7.04 AM'
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I recently ran into this situation. My focus was on clean readability and reusability.
Use
(See function definition below)
timeUnits(86400000) // {days: 1, hours: 0, minutes: 0, seconds: 0, ms: 0}
Then you can use the data to do whatever you want (like build a string).
Other examples:
timeUnits(214870123) // {days: 2, hours: 11, minutes: 41, seconds: 10, ms: 123}
timeUnits('70123') // null
Function
/**
* Converts milliseconds into greater time units as possible
* @param {int} ms - Amount of time measured in milliseconds
* @return {?Object} Reallocated time units. NULL on failure.
*/
function timeUnits( ms ) {
if ( !Number.isInteger(ms) ) {
return null
}
/**
* Takes as many whole units from the time pool (ms) as possible
* @param {int} msUnit - Size of a single unit in milliseconds
* @return {int} Number of units taken from the time pool
*/
const allocate = msUnit => {
const units = Math.trunc(ms / msUnit)
ms -= units * msUnit
return units
}
// Property order is important here.
// These arguments are the respective units in ms.
return {
// weeks: allocate(604800000), // Uncomment for weeks
days: allocate(86400000),
hours: allocate(3600000),
minutes: allocate(60000),
seconds: allocate(1000),
ms: ms // remainder
}
}
It's written in such a way so that you can easily implement other units (for example, where I commented out implementation for weeks) so long as you know their worth in milliseconds.
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A Date object can be constructed from milliseconds:
const date = new Date(0, 0, 0, 0, 0, 0, milliseconds);
The time can then be obtained in any number of formats. The one you require matches that used in the United Kingdom, locale en-GB:
const hms = d.toLocaleTimeString('en-GB');
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If you're using typescript, this could be a good thing for you
enum ETime {
Seconds = 1000,
Minutes = 60000,
Hours = 3600000,
SecInMin = 60,
MinInHours = 60,
HoursMod = 24,
timeMin = 10,
}
interface ITime {
millis: number
modulo: number
}
const Times = {
seconds: {
millis: ETime.Seconds,
modulo: ETime.SecInMin,
},
minutes: {
millis: ETime.Minutes,
modulo: ETime.MinInHours,
},
hours: {
millis: ETime.Hours,
modulo: ETime.HoursMod,
},
}
const dots: string = ":"
const msToTime = (duration: number, needHours: boolean = true): string => {
const getCorrectTime = (divider: ITime): string => {
const timeStr: number = Math.floor(
(duration / divider.millis) % divider.modulo,
)
return timeStr < ETime.timeMin ? "0" + timeStr : String(timeStr)
}
return (
(needHours ? getCorrectTime(Times.hours) + dots : "") +
getCorrectTime(Times.minutes) +
dots +
getCorrectTime(Times.seconds)
)
}
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In my implementation I used Moment.js:
export default (value) =>
const duration = moment.duration(value);
const milliseconds = duration.milliseconds();
const seconds = duration.seconds();
const minutes = duration.minutes();
const hours = duration.hours();
const day = duration.days();
const sDay = `${day}d `;
const sHours = (hours < 10) ? `0${hours}h ` : `${hours}h `;
const sMinutes = (minutes < 10) ? `0${minutes}' ` : `${minutes}' `;
const sSeconds = (seconds < 10) ? `0${seconds}" ` : `${seconds}" `;
const sMilliseconds = `${milliseconds}ms`;
...
}
Once got the strings, I composed them as I want.
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I works for me as i get milliseconds=1592380675409 using javascript method getTime() which returns the number of milliseconds between midnight of January 1, 1970 and the specified date.
var d = new Date();//Wed Jun 17 2020 13:27:55 GMT+0530 (India Standard Time)
var n = d.getTime();//1592380675409 this value is store somewhere
//function call
console.log(convertMillisecToHrMinSec(1592380675409));
var convertMillisecToHrMinSec = (time) => {
let date = new Date(time);
let hr = date.getHours();
let min = date.getMinutes();
let sec = date.getSeconds();
hr = (hr < 10) ? "0"+ hr : hr;
min = (min < 10) ? "0"+ min : min;
sec = (sec < 10) ? "0"+ sec : sec;
return hr + ':' + min + ":" + sec;//01:27:55
}
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Explain your code, code without explanation is bad code. – Alexandre Elshobokshy Jun 16 '20 at 14:31
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A refactor from @dusht to ES6+ and more functional:
const addPrefix = time => time < 10 ? '0' + time : time;
const toHours = time => addPrefix(Math.floor((time / (1000 * 60 * 60)) % 24));
const toMinutes = time => addPrefix(Math.floor((time / (1000 * 60)) % 60));
const toSeconds = (ime => addPrefix(Math.floor((time / 1000) % 60));
const toMiliseconds = time => Math.floor((time % 1000) / 100);
const milisecondToHoursAndMinute = time => {
const hours = toHours(time);
const minutes = toMinutes(time);
const seconds = toSeconds(time);
const miliseconds = toMiliseconds(time);
return `${hours}:${minutes}:${seconds}.${miliseconds}`
}
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let dateTimeStr = new Date(1949778000);
dateTimeStr = Math.floor(dateTimeStr/86400000) +' days '+ dateTimeStr.getHours() +' hours '+ dateTimeStr.getMinutes() +' minutes '+ dateTimeStr.getSeconds() +' seconds';
console.log(dateTimeStr);
You don't have to calculate the days if you don't need them
"22 days 16 hours 36 minutes 18 seconds"
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