java complex statement execution order

Question

System.out.println(info + ": " + ++x);

is this statement equivalent to

x++;
System.out.println(info + ": " + x);

and

System.out.println(info + ": " + x++);

is equivalent to

System.out.println(info + ": " + x);
x++;

As JVM can only process one statement at a time, does it divides these statements like this?

Probably a duplicate of ... well, hundreds of other questions ( http://stackoverflow.com/questions/484462/difference-between-i-and-i-in-a-loop and others) — Marco13, Aug 18 '14 at 08:22

Szymon · Answer 1 · 2013-10-27T05:06:46.550

3

Yes and yes.

++x will be executed before the containing statement, ie the value of x will be incremented before it's used.

x++ will be executed after the containing statement, ie the value will be used and then the variable x incremented.

To be clear: in both cases the value of variable x will be changed.

edited Oct 27 '13 at 05:06

answered Oct 27 '13 at 04:58

Szymon

I am asking while executing that statement how will jvm will divide it? – Ruturaj Oct 27 '13 at 05:09
This answer is not correct. x++ will be post-incremented after the value is obtained. – user207421 Oct 27 '13 at 09:23
1

@EJP that's what I said above – Szymon Oct 27 '13 at 23:10

1 Answers1