26

Is there something similar to DATEFROMPARTS(year, month, day) in SQL Server 2008? I want to create a date using the current year and month, but my own day of the month. This needs to be done in one line in order to be used in a computed column formula.

For Example (I'm not sure if it works because I do not have SQL Server 2012):

DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 3)

Is there a way to do this in SQL Server 2008?

DATEFROMPARTS Seems only available in SQL Server 2012 (link)

Luke Girvin
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Jaiesh_bhai
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4 Answers4

25

Using the 3 from your example, you could do this:

dateadd(dd, 3 -1, dateadd(mm, datediff(mm,0, current_timestamp), 0))

It works by finding the number of months since the epoch date, adding those months back to the epoch date, and then adding the desired number of days to that prior result. It sounds complicated, but it's built on what was the canonical way to truncate dates prior to the Date (not DateTime) type added to Sql Server 2008.

You're probably going to see other answers here suggesting building date strings. I urge you to avoid suggestions to use strings. Using strings is likely to be much slower, and there are some potential pitfalls with alternative date collations/formats.

Joel Coehoorn
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    @MartinSmith Thanks, fixed :o Forgot for a moment that I'd be adding the days to a 1 instead of a 0. – Joel Coehoorn Oct 22 '13 at 17:05
  • There seems to be a syntax error somewhere, I don't see a syntax error after the edits that have been made. `Msg 102, Level 15, State 1, Line 1 Incorrect syntax near 'dd'.` – Jaiesh_bhai Oct 22 '13 at 17:12
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    @Jaiesh_bhai I was also missing a closing parentheses at one point. If I put a `select ` in front of what's there now and paste it directly into a query window in Management Studio, I get `2013-10-03 00:00:00.000` if I run it right now. – Joel Coehoorn Oct 22 '13 at 17:14
  • Oh okay! Thanks that was dumb of me. I forgot the `SELECT`. This is exactly what I am looking for. – Jaiesh_bhai Oct 22 '13 at 17:17
25

You could use something like this to make your own datetime:

DECLARE @year INT = 2012
DECLARE @month INT = 12
DECLARE @day INT = 25

SELECT CAST(CONVERT(VARCHAR, @year) + '-' + CONVERT(VARCHAR, @month) + '-' + CONVERT(VARCHAR, @day)
 AS DATETIME)
Ken Richards
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  • It would probably be less error-prone to convert the year to CHAR(4) and the month and day to CHAR(2). In your example you have them hardcoded but in normal use those could be coming from somewhere else and it could cause problems if these parameters weren't the expected length. – levininja Dec 11 '19 at 17:33
4
CREATE FUNCTION  DATEFROMPARTS
(
    @year int,
    @month int,
    @day int
)
RETURNS datetime
AS
BEGIN

     declare @d datetime

     select @d =    CAST(CONVERT(VARCHAR, @year) + '-' + CONVERT(VARCHAR, @month) + '-' + CONVERT(VARCHAR, @day) AS DATETIME)
    RETURN  @d 

END
GO
AlejandroR
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0
CREATE FUNCTION  DATEFROMPARTS
(
    @year int,
    @month int,
    @day int
)
RETURNS datetime
AS
BEGIN

    declare 
    @sy varchar(max)
    ,@sm varchar(max)
    ,@sd varchar(max)
    ;

    set @sy = convert(varchar(max),@year);
    set @sm = (case when @month<10 then '0' else '' end) + 
    convert(varchar(max),@month);
    set @sd = (case when @day<10 then '0' else '' end) + 
    convert(varchar(max),@day);

    RETURN  convert(datetime, @sy + '-' + @sm + '-' + @sd + 'T00:00:00.000');
END
Ivano Fioravanti
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  • As it’s currently written, your answer is unclear. Please [edit] to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Dec 11 '21 at 22:14