Pattern matching with grep

Question

I have a full path of a file say hai/hello/home/something/file.txt .How can I get file.txt as output eliminating full path?

How to do that with grep?

Why does it have to be with grep? – JB. Oct 03 '13 at 09:31 — JB., Oct 03 '13 at 09:31

score 2 · Answer 1 · answered Oct 03 '13 at 07:03

2

#!/usr/bin/perl
use File::Spec;
use File::Basename;
$n="hai/hello/home/something/file.txt";
my $m = basename $n;
print "$m";

answered Oct 03 '13 at 07:03

pkm

score 1 · Answer 2 · answered Oct 03 '13 at 06:55

1

You don't strictly need grep for this, but if you insist, this should work:

grep -o -e "\w*\.\w*$"

Optionally, consider the command basename:

basename hai/hello/home/something/file.txt

answered Oct 03 '13 at 06:55

Nikhil

Please leave a comment if down-voting, explaining why. Otherwise it helps nobody. – Nikhil Oct 03 '13 at 09:30

score 1 · Answer 3 · answered Oct 03 '13 at 06:55

1

You can do it using sed:

$ echo hai/hello/home/something/file.txt | sed "s|.*/||g"
file.txt

$ basename hai/hello/home/something/file.txt
file.txt

answered Oct 03 '13 at 06:55

mvp

3 Answers3