19
function areaMe(area) {
    var barea = $('#barea').val();
    if (barea.indexOf(area) != -1) {
        alert ("..." + barea + "..." + area + "...");
        barea.replace(area, "cu"); // Remove
        alert ("..." + barea + "..." + area + "...");
    }
    else {
        barea += area + ' '; // Include.
    }
    $('#barea').val(barea);
}
Peter Mortensen
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Paulo Bueno
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3 Answers3

57
barea = barea.replace(area, "cu")

You need to assign it since String.prototype.replace isn't a mutator method.

meder omuraliev
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9

You need to assign the replaced value back to your variable:

barea = barea.replace(area, "cu");
Gumbo
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0

barea = barea.replace(area, "cu")

WisdomFusion
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