imagecreatefrompng is not working at all

Question

I already checked the file with mime type. If it is jpg or gif it is working perfectly with

$src = imagecreatefromjpeg($tmpName);

and

$src = imagecreatefromgif($tmpName);

but if the image is png $src = imagecreatefrompng($tmpName);

src variable is empty in the png case, but in jpg and gif it is showing it's resource id.

would someone tell me what i need to do?

$finfo = finfo_open(FILEINFO_MIME_TYPE);
    $mime = finfo_file($finfo, $_FILES['photo']['tmp_name']);
    unset($_FILES["photo"]["type"]);
    $_FILES["photo"]["type"] = $mime;

    if ((($_FILES["photo"]["type"] == "image/gif") || ($_FILES["photo"]["type"] == "image/jpeg") || ($_FILES["photo"]["type"] == "image/jpg") || ($_FILES["photo"]["type"] == "image/pjpeg") || ($_FILES["photo"]["type"] == "image/x-png") || ($_FILES["photo"]["type"] == "image/png")) && in_array($extension, $allowedExts)) {

        if ($_FILES["photo"]["error"] > 0) {
            echo "Error uploading file <a href='step-1.php'> Try again. </a>";
            $image_check = 0;
            exit;
        } else {

            $image_check = 1;
            $fileName = $_FILES['photo']['name'];
            $tmpName = $_FILES['photo']['tmp_name'];
            $fileSize = $_FILES['photo']['size'];
            $fileType = $_FILES['photo']['type'];
            list($width1, $height1, $typeb, $attr) = getimagesize($tmpName);

            //$filePath = $uploadDir . $fileName;

            $size = filesize($_FILES['photo']['tmp_name']);

             $ext = $_FILES["photo"]["type"];

            if ($ext == 'image/jpeg' || $ext == 'image/jpg') {
            $src = imagecreatefromjpeg($tmpName);
        } else if ($ext == 'image/gif') {
            $src = imagecreatefromgif($tmpName);
        }
            else if(($ext=='image/png')||($ext=='image/x-png'))
         {
            $src = imagecreatefrompng($tmpName);
           }
       $newwidth1 = 624;


        $newheight1 = ($height1 * $newwidth1) / ($width1);
        $tmp = imagecreatetruecolor($newwidth1, $newheight1);

        imagecopyresampled($tmp, $src, 0, 0, 0, 0, $newwidth1, $newheight1, $width1, $height1);
        $filename = "resources/images/" . $append . $_FILES['photo']['name'];

         if ($ext == 'image/jpeg' || $ext == 'image/jpg') {
            imagejpeg($tmp, $filename, 90);
        } else if ($ext == 'image/gif') {
            imagegif($tmp, $filename, 90);
        }
        else if(($ext=='image/png')||($ext=='image/x-png'))
        {

            imagepng($tmp, $filename, 90);
        }

In general that function works fine. We'll need something more to go on to help you with your *specific* case. — deceze, Sep 16 '13 at 05:56
this code is working perfectly for jpg and gif images but not for png. — user2679683, Sep 16 '13 at 06:10
yeah, I tried that header('Content-Type: image/png'); imagepng($tmp, $filename, 90);but it is not working . — user2679683, Sep 16 '13 at 06:11
Have you enabled full error reporting (ie `E_ALL`)? You may find `$src` isn't being set at all. Also, rather than rely on the uploaded `type` property, why not look at `$typeb` and compare it to one of the `IMAGETYPE_*` constants? See [here](https://gist.github.com/philBrown/880506#file-imagemanipulator-php-L43) for an example — Phil, Sep 16 '13 at 06:22

MaxEcho · Answer 1 · 2013-09-16T06:40:27.997

9

Write a file

<?php
    phpinfo();
?>

Browse it, you will see JPG Support and GIF create Support are enabled but PNG Support is disabled.

Enable PNG Support, it will work.

enter image description here

edited Sep 16 '13 at 06:40

answered Sep 16 '13 at 06:28

MaxEcho

13,989
6
76
86

Answer is edited, you have need to enable PNG Support perhaps – MaxEcho Sep 16 '13 at 06:44
Will you try, else if((strtolower($ext)=='image/png')||(strtolower($ext)=='image/x-png')) – MaxEcho Sep 16 '13 at 07:01
Another thing, have to check the image you are trying is valid png or not. – MaxEcho Sep 16 '13 at 07:22
mime type is used to check the image type. I guess this is validate whether the image is png or not.. If I am wrong correct me. – user2679683 Sep 16 '13 at 07:34

score 7 · Answer 2 · answered Jun 12 '15 at 04:35

7

Change from

imagepng($tmp, $filename, 90);

to

imagepng($tmp, $filename);

answered Jun 12 '15 at 04:35

PgKc

71
1
1

1

Note that [`imagepng`](https://www.php.net/manual/en/function.imagepng.php) expects a `quality` value between -1 and 9. I assume this is the reason for the proposed change. – showdev Jul 22 '19 at 22:46

imagecreatefrompng is not working at all

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