How to roundup a Double value up to two precision

Question

I have a Double value Double val = 49.569632

How can I roundup the val to get 49.57

Also keep in mind that Double and double are different things and you probably would want double... unless you really know what you are doing... — sashkello, Sep 12 '13 at 06:33

score 5 · Accepted Answer · edited May 23 '17 at 12:23

5

You can use the DecimalFormat.

double d = 4.569632;
DecimalFormat df = new DecimalFormat("#.##");
System.out.print(df.format(d));

Or you can use the below method as mentioned in this answer as Luiggi Mendoza suggested.

public static double round(double value, int places) {
    if (places < 0) throw new IllegalArgumentException();

    BigDecimal bd = new BigDecimal(value);
    bd = bd.setScale(places, BigDecimal.ROUND_HALF_UP);
    return bd.doubleValue();
}

edited May 23 '17 at 12:23

Community

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answered Sep 12 '13 at 06:32

Rahul

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It would be better using `BigDecimal` as posted in the possible duplicate Q/As – Luiggi Mendoza Sep 12 '13 at 06:33
DecimalFormat is perfect for my instance. Thank you. – Sajeev Sep 12 '13 at 11:44
Glad to be of help! :) – Rahul Sep 12 '13 at 11:45

score 1 · Answer 2 · answered Sep 12 '13 at 07:07

A simple way to round is when printing

double val = 49.569632; // this should be a primitive, not an object
System.out.printf("%.2f%n", val);

or you can round the value first

double rounded = Math.round(val * 1e2) / 1e2;
System.out.println(rounded);

IMHO Using BigDecimal is slower, more complicated to write and no less error prone than using double if you know what you are doing. I know many developer prefer to use a library than write code themselves. ;)

How to roundup a Double value up to two precision

2 Answers2